ANSWER CHOICE C
We have been given two box plots representing attendance at a local movie theater and high school basketball games. WE are asked to choose the correct option about the measure the spread of the data represented by box plots.
Since we know that Standard deviation is not a good measure of spread in highly skewed data. IQR is better measure of spread for highly skewed data.
We can see that box plot representing attendance at movies is right skewed, therefore, mean will be greater than median and SD will not be a good measure of spread.
Box plot representing basket-ball games attendance is left skewed left,therefore, mean will be less than median and SD will not be a good measure of spread.
Our both box plots are highly skewed, therefore, the IQR is the best measurement of spread for games and movies and option C is the correct choice.
Dang, that sucks.........
Answer:
See explanation
Step-by-step explanation:
The triangles below are congruent and their corresponding parts are marked.
a) Angles marked with one arc are congruent, so 
Angles marked with two arcs are congruent, so 
Angles marked with three arcs are congruent, so 
b) Sides marked with one segment are congruent, so 
Sides marked with two segments are congruent, so 
Sides marked with three segments are congruent, so 
c) Name teo congruent triangle following the congruence of angles:

499 - 100%
599 - x
x = 599*100/499 = 120.04
x-100% = 120.04-100 = 20.04
Answer: The price increased by 20%.