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2 years ago

Please Help me answer all 4 questions with a full explanation so I can solve the rest on my own.

Mathematics

1 answer:

Nata [24]2 years ago

6 0

$\\ \rm\Rrightarrow (2x^2)^3.2yx^0=8x^6.2y=16x^6y$

$\\ \rm\Rrightarrow (2x^4y^3)^3.2x^4y^4=8x^{12}y^6.2x^4y^4=16x^{16}y^{10}$

$\\ \rm\Rrightarrow (m^3n^0(2m^3n^2)^4)^2=(m^316m^{12}n^8)^2=(16m^{15}n^8)^2=256m^{30}n^{16}$

$\\ \rm\Rrightarrow (2xy^3)^2.2x^2y^0=4x^2y^6.2x^2=8x^4y^6$

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Parallelogram PQRS is shown. m/S=(3x), m/R=120, and m/Q=(2y). Find the value of y.A.

fomenos

Option B. From the parallelogram PQRS the value of y is given to be 30

<h3>How to solve for the value of y from the parallelogram</h3>

In order to get the value of y we have to use the formula

2y + 120 = 80

where the value 120 is the angle that is stated as 120 from the question

2y = 180 - 120

2y = 60

y = 60 / 2

y = 30

Hence the value of y = 30

We can go ahead to get the value of x as well

3x + 120 = 180

take the like terms

3x = 180 - 120

3x = 60

divide through by 3 to get x

60 / 3 = x

20 = x

Read more on parallelograms here: brainly.com/question/24056495

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7 0

1 year ago

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

Both polygons are similar. Find the scale factor of the smaller figure to the larger figure (please explain how you got the answ

Mice21 [21]

Well what i did was subtract 10 from 15 it get 5 for one side length and the other would be 24-16= 8. the scale factor would be +5 and + 8.

3 0

3 years ago

Simplify.<br> -9 -5 -7<br> х<br> Y Z<br> 2 6 3<br> X Y Z

krok68 [10]

Answer:

$= {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$

Step-by-step explanation:

$= \frac{ {x}^{ - 9} {y}^{ - 5} {z}^{ - 7} }{ {x}^{2} {y}^{6} {z}^{3} } \\ = {x}^{ - 9 - 2} {y}^{ - 5 - 6} {z}^{ - 7 - 3} \\ = {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$

7 0

3 years ago

You fly a hot air balloon 3.5 miles above the ground. What is the measure of BD⌢, the portion of Earth that you can see? Round y

STatiana [176]

Answer:

$\Delta s \approx 334.545\,m$

Step-by-step explanation:

Let assume that Earth is a sphere, the following trigonometric diagram is constructed and presented below. The central angle is given by this inverse trigonometric equation:

$\theta = 2\cdot \cos^{-1} \left(\frac{r}{r+h} \right)$

$\theta = 2\cdot \cos^{-1}\left(\frac{4000\,mi}{4000\,mi+3.5\,mi} \right)$

$\theta = 4.792^{\circ}$

The distance of the portion of Earth that can be seen is:

$\Delta s = \frac{4.792^{\circ}}{360^{\circ}}\cdot (2\pi)\cdot (4000\,mi)$

$\Delta s \approx 334.545\,m$

7 0

3 years ago