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Masja [62]
3 years ago
13

20! / 16! = a 24 b 11,628 c 116,280 d A number too big to compute

Mathematics
1 answer:
disa [49]3 years ago
6 0

20! / 16!  =

20*19*18*17*16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1

divided by

16*15*14*13*12*11*10*9*8*7*6*5*4*3*2*1

 equals C. 116,280

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WILLL GIVE BRAINLEST <br> WILL GUVE BRAINLEST<br> Photo is attached!! Thanks I appreciate if u help
sp2606 [1]

Answer:

1 false

2 true

3 true

4 false

5 true

Step-by-step explanation:

f(a) = (2a - 7 + a^2) and g(a) = (5 – a).

1 false f(a) is a second degree polynomial and g(a) is a first degree polynomial

When added together, they will be a second degree polynomial

2. true  When we add and subtract polynomials, we still get a polynomial, so it is closed under addition and subtraction

3.  true  f(a) + g(a) = (2a - 7 + a^2) + (5 – a)

Combining like terms = a^2 +a -2

4.  false   f(a) - g(a) = (2a - 7 + a^2) - (5 – a)

Distributing the minus sign (2a - 7 + a^2) - 5 + a

Combining like terms  a^2 +3a -12

5.  true  f(a)* g(a)  = (2a - 7 + a^2)  (5 – a).

Distribute

                      (2a - 7 + a^2)  (5)  – (2a - 7 + a^2)  (a)

                       10a -35a +5a^2 -2a^2 -7a +a^3

Combining like term

-a^3 + 3 a^2 + 17 a - 35

3 0
3 years ago
Find the solutions of the quadratic equation 14x^2+9x+10=014x
Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

so

a=14\\b=9\\c=10

substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}

x=\frac{-9(+/-)\sqrt{-479}} {28}

Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

5 0
3 years ago
How??????????????????????
Digiron [165]

Answer:

y=-1/3x+7

Step-by-step explanation:

y=mx+c

m=-1/3, c=7

y=-1/3x+7

5 0
3 years ago
Identify which trigonometry function you will use and find
poizon [28]

Answer:

a35

Step-by-step explanation:

the sine is greater than the cosn

7 0
3 years ago
NEED HELP PLEASE FAST!
Aleks [24]
For one it would be c and d 
Two x is greater than seven 
three would be x is greater than or equal to 6 
Four would be subtract eight from both sides you get 24 and then divide by negative four which gets you negative six but then you have to turn the sign around. Number set would be anything above negative six,so like negative five, 52, and one
Five would be subtract 3 from both sides giving you 5 on the right side and then multiply by six on both sides giving you thirty on the right side, resulting in x is greater than or equal to thirty. Three numbers that would work would be thirty, fifty nine, and thirty five.
4 0
3 years ago
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