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mart [117]
3 years ago
14

125,000 to 117,500 what is the percent decrease in value

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

6%

Step-by-step explanation:

Decrease in value = 125 000 - 117 500

= 7500

Percentage decrease = (7500 ÷ 125 000) × 100

= 6%

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Solve K/2 + 5 - 2k = 6k
pantera1 [17]

Answer:

k = 2/3 is the answer!

Step-by-step explanation:

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3 years ago
Two​-thirds of the​ T-shirts in a​ T-shirt shop are blue. Three​-fifths of those​ T-shirts are on sale. ​One-half of the blue​ T
katrin2010 [14]

Let, total number of T-shirts are x.

Number of blue T-shirts = (2/3)x = 2x/3 .

Number of blue shirts on sale = (3/5)(2x/3) = 2x/5 .

Number of medium sized blue shirts on sale = (1/5)(2x/5) = 2x/25 .

Fraction of the​ shop's T-shirts are blue​ T-shirts that are on sale and are size​ medium = \dfrac{2x/25}{x}= 2/25 . ( Number of medium sized blue shirts on sale divided by total number of T-shirts )

Hence, this is the required solution.

5 0
4 years ago
Is 2.5 rational, integer, whole,natural, irrational
Lyrx [107]

Out of that particular list, the only description
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3 0
3 years ago
A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand
Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

\mu_G = 15

s_G = \frac{4.2}{\sqrt{35}} = 0.71

The distribution of life spans for electric ranges has a mean of 13.4 years and a standard deviation of 3.7 years. Sample of 40:

This means that:

\mu_E = 13.4

s_E = \frac{3.7}{\sqrt{40}} = 0.585

Which of the following best describes the sampling distribution of the difference in mean life span of gas ranges and electric ranges?

Shape is approximately normal.

Mean:

\mu = \mu_G - \mu_E = 15 - 13.4 = 1.6

Standard deviation:

s = \sqrt{s_G^2+s_E^2} = \sqrt{0.71^2+0.585^2} = 0.92

So the correct answer is given by option b.

8 0
3 years ago
What is the volume of the rectangular prism 10.4mm 5mm 8mm
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The answer too this problem is 416.
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