The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0. i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0 0.0004t = 0.06 t = 0.06/0.0004 = 150 Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5 Therefore, the maximum concentration is 4.5mg/L
