An arithmetic sequence takes the form

where

is the common difference between terms. You can solve for

in terms of any of the previous terms of the sequence:

for some integer

Continuing in this way, you know that the sequence can be defined explicitly in terms of the first term


Given that the 4th term is

and the 11th term is

, you have the following system of equations.

Solving this system for the two unknowns yields

and

.
So, the sequence is given explicitly by
Hi!
Shawna is correct because since it's multiplied to the 5-n you have to do the opposite which is division.
Dexter is also correct because after distributing you can continue solving, there is nothing wrong with that.
Hope this helps!
Answer:
It will be "q+5"
Step-by-step explanation:
When you add a number and a letter you just leave them like that. If you would to have a number multiplying a letter like "5q" and something else like "3q" when you add them together you will get "5q+3q=8q" In this case you can add them together because the number is multiplying the letter.
Answer: X > 100
Step-by-step explanation:
X - 19 < 81
Once the less than sign is turned over
X > 81 +19
X > 100
Thus, the value of X must be greater than 100
Write the equation: x + 42 + 30 = 131
Combine like terms: x + 72 = 131
Subtract 72 from both sides: x = 59