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Tresset [83]
4 years ago
12

1.

Chemistry
2 answers:
Tanzania [10]4 years ago
4 0

Answer:

1.b

2.true

3.unicellular

Explanation:

Vladimir [108]4 years ago
3 0

Answer:

1. chitin

2.true

3.unicellular

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A sample of gas has a volume of 2.0 liters at a pressure of
aleksklad [387]
X= 2.0atm when u substitute for V1P1=V2P2
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3 years ago
CO2 is an element. True False
Reil [10]

Answer:False

Explanation:co2 or carbon dioxide is a  compound not an element, you can even check this on the periodic table

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4 years ago
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A chemistry student conducted several different procedures. Which of the following procedures best demonstrates the law of conse
Vsevolod [243]

Answer:

combining 2 grams of copper and 4 grams of sulfur to make 6 grams of copper sulfate

Explanation:

The Law of Conservation of Mass states that matter cannot be created or destroyed in chemical reactions. It posits that the mass of a substance remains unchanged after undergoing a chemical process.

Therefore, according to the question, the procedure that best demonstrates the law of conservation of mass after the chemistry student conducted different procedures is option D.

This is because, the mass of copper and sulfate did not change but merely combined to form a compound.

7 0
3 years ago
The geological time scale is divided up and organized according to what life forms existed on earth.
Ivanshal [37]

Answer:

true

Explanation:

Geologic time is divided into four large segments called Eons: Hadean, Archean, Proterozoic, and Phanerozoic. The Phanerozoic Eon isdivided into Eras: Paleozoic, Mesozoic, and Cenozoic. The divisions among Eras reflect major changes in the fossil record, including the extinction and appearance of new life forms.

8 0
3 years ago
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A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v
hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

    = (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

     = (-75000 J) - ( -13071 J)

     =  -75000 J + 13071 J

     = -61929 J

Total energy change, ΔE = -61.929 kJ

3 0
4 years ago
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