Answer:
Moles of NaCl formed is 6.0 moles
Explanation:
We are given the equation;
2 Na(s) + Cl₂(g) → 2 NaCl(s)
- Moles of Na is 6.0 moles
- Moles of Cl₂ is 4.0 moles
From the reaction;
2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl
In this case;
6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.
Thus, the rate limiting reagent is sodium.
But, 2 moles of sodium reacts to form 2 moles of NaCl
Therefore;
Moles of NaCl = Moles of Na
= 6.0 moles
Thus, moles of sodium chloride produced is 6.0 moles
The enthalpy of the reaction can be obtained from the enthalpies of formation as -16.2 kJ/mol.
<h3>What is the enthalpy of reaction?</h3>
We know that any time that there is a chemical reaction, there is an interaction that place between the reactants and the products and as such we are going to get new substances and these are the substances that I have referred to here as the products of the reaction.
In this case, we are asked to obtain the enthalpy change of the reaction. This tells us the heat that could have been absorbed or evolved in the reaction. We have to at this point know that the enthalpy change of the reaction gotten from;
Sum of enthalpy of the products - Sum of enthalpy of the reactants
ΔH = [(-484.5)] - [(-393.5) + (-74.8)]
ΔH = (-484.5) + 468.3
ΔH = -16.2 kJ/mol
Learn more about enthalpy:brainly.com/question/3393755
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