We want to solve Q = mcΔT for the liquid water; its change in temperature will tell us the amount of thermal energy that flowed out of the reaction. The specific heat, c, of water is 4.184 J/g °C.
Q = (72.0 g)(4.184 J/g °C)(100 °C - 25 °C) = 22593.6 J
Q ≈ 2.26 × 10⁴ J or 22.6 kJ (three significant figures).
Answer:
978.19° C
Explanation:
P1V1/T1 =P2V2/T2 Since the pressure is constant, this can be written as
V1/T1 = V2/T2 RE-ARRANGE TO
V2 * T1/V1 = T2 Note: T must be in Kelvin!!
1.5 L * (273.15 + 23) / (.355 L ) = T2 = 1251.338 K =978.19 C
We use prefixes in ionic compounds Don't use numeric prefixes like mono, di, tri, etc. when naming ionic compounds - they are used only to denote covalent molecular compounds.
Change(A chemical reaction.)
