Answer: The magnetic field<span> of a bar </span>magnet<span> is </span>strongest<span> at either pole of the </span>magnet<span>. It is equally strong at the north pole compared with the south pole. The force is weaker in the middle of the </span>magnet <span>and halfway between the pole and the center.
hope this helps</span>
The reaction will proceed in the reverse direction in order to increase the concentrations of both CO and H2O and decrease that of CO2 and H2 until Q = K.
The reaction will proceed to the left
Step 1: The balanced equation
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
Step 2: Data given
Kp = 2.7
Number of moles of CO = 0.13 mol
Number of moles of H2O = 0.56 mol
Number of moles of CO2 = 0.62 mole
Number of moles of H2 = 0.61 mol
Volume = 2.0L
Step 3: Calculate Q
Pco = 0.13 / 1.92 P
Ph2o = 0.56 / 1.92 P
Pco2 = 0.62/1.92 P
Ph2 =0.61 / 1.92 P
Q = [CO2][H2] / [CO][H2O] = 5.2
Q > Kp The reaction will proceed to the left
The reaction will proceed in the reverse direction in order to increase the concentrations of both CO and H2O and decrease that of CO2 and H2 until Q = K.
To know more about concentrations of both CO and H2O
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Answer:
Neutral.
Explanation:
Protons have a positive charge. In this problem there are 12.
Electrons have a negative charge. In this problem there are 12.
Neutrons have a neutral charge that isn't relevant tot the overall charge, it can be ignored.
#protons - #e- = charge
12 - 12 = 0
The protons and electrons balance each other out, resulting in a 0 net charge. This means the atom has a neutral charge.
H20. 2 of hydrogen and oxygen
Answer:
18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Explanation:
Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.
The decomposition of mercury oxide is given by the chemical equation below:
2HgO ----> 2Hg + O₂
2 moles of HgO decomposes to produce 1 mole of Hg
2 moles of HgO has a mass of 433.2 g
433.2 g of HgO produces 216.6 g of Hg
18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg
Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury