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erastovalidia [21]
3 years ago
7

does anyone know a good way to remember the difference between the domain and range?? if so can you tell me??

Mathematics
2 answers:
lara [203]3 years ago
7 0
The domain are the x values and the range is the opposite of that which are the y values
Basile [38]3 years ago
6 0
The domain is the values that x is allowed to be and range is the values that the y's end up being
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Ebonie invests in $2500 today in an account earning 7%. How much will she have in 5 years?
nikdorinn [45]

Answer:

Amount she Receive in 5 years = $3506.37

Step-by-step explanation:

Given in question as

Ebonie invests amount in account = P = $2500

The interest rate she will have = 7%

The amount will keep in account for 5 years

Now we apply compound interest (CI ) to determine how much she will receive after 5 years ,

So , for CI

Amount = principal ( 1 + \frac{Rate}{100} ^ T     ,where T is Time

So, A = 2500 ( 1 +\frac{7}{100})^5

Or, A = 2500 (1.40255)

Or, A = $3506.37

Hence Amount she will receive $ 3506.37  Answer

3 0
3 years ago
The sum of two numbers is 39, twice the first number plus three times the second number is 101 find the numbers
bezimeni [28]
The two numbers are 23 and 16 and the method is shown algebraically using simultaneous equations in the photo

3 0
3 years ago
A business was valued at £80000 at the start of 2013. In 5 years the value of this business raised to £95000. this is equivalent
Yuri [45]

the yearly increase of x% assumes is compounding yearly, so let's use that.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\£95000\\ P=\textit{original amount deposited}\dotfill &\£80000\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases}

95000=80000\left(1+\frac{~~ \frac{r}{100}~~}{1}\right)^{1\cdot 5}\implies \cfrac{95000}{80000}=\left( 1+\cfrac{r}{100} \right)^5 \\\\\\ \cfrac{19}{16}=\left( 1+\cfrac{r}{100} \right)^5\implies \sqrt[5]{\cfrac{19}{16}}=1+\cfrac{r}{100}\implies \sqrt[5]{\cfrac{19}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[5]{\cfrac{19}{16}}=100+r\implies 100\sqrt[5]{\cfrac{19}{16}}-100=r\implies 3.5\approx r

4 0
2 years ago
Angles ∠ABC= x and ∠CBD=(2y+4) are complementary. ∠CBD and ∠DBE=(3y+x) are supplementary.
Basile [38]

The missing question is find x , y and the measure of each angle

The values of x and y are x = 28 and y = 30

The measures of ∠ABC is 26°, ∠CBD is 64° and ∠DBE is 116°

Step-by-step explanation:

Let us revise the meaning of complementary angles and supplementary angles

  • Two angles are complementary if their sum is 90°
  • Two angles are supplementary if their sum is 180°

∵ ∠ABC = x

∵ ∠CBD = 2y + 4

∵ ∠ABC and ∠CBD are complementary

- That means their sum is 90°, add their values and equate

   the sum by 90

∴ x + (2y + 4) = 90

∴ x + 2y + 4 = 90

- Subtract 4 from both sides

∴ x + 2y = 86 ⇒ (1)

∵ ∠DBE = (3y + x)

∵ ∠CBD and ∠DBE are supplementary

- That means their sum is 180°, add their values and equate

   the sum by 180

∵ ∠CBD = (2y + 4)

∴ (2y + 4) + (3y + x) = 180

- Add like terms

∴ x + 5y + 4 = 180

- Subtract 4 from both sides

∴ x + 5y = 176 ⇒ (2)

Now we have a system of equations to solve them

Subtract equation (1) from equation (2) to eliminate x

∵ 3y = 90

- Divide both sides by 3

∴ y = 30

- Substitute the value of y in equation (1) to find x

∵ x + 2(30) = 86

∴ x + 60 = 86

- Subtract 60 from both sides

∴ x = 26

∵ ∠ABC = x

∴ The measure of angle ABC is 26°

∵ ∠CBD = 2y + 4

∴ ∠CBD = 2(30) + 4 = 60 + 4 = 64°

∴ The measure of angle CBD is 64°

∵ ∠DBE = 3y + x

∴ ∠DBE = 3(30) + 26 = 90 + 26 = 116°

∴ The measure of angle DBE is 116°

The values of x and y are x = 28 and y = 30

The measures of ∠ABC is 26°, ∠CBD is 64° and ∠DBE is 116°

Learn more:

You can learn more about the complementary angles and supplementary angles in brainly.com/question/10483199

#LearnwithBrainly

6 0
3 years ago
Colby and Sarah sold newspapers this past summer. Colby earned $4.50 for each newspaper he sold. Sarah's earnings were $35 less
aksik [14]
D. <span>Colby and Sarah sold newspapers this past summer. Colby earned $4.50 for each newspaper he sold. Sarah's earnings were $35 less than Colby's at the end of the summer. The following expression shows Sarah's earnings: 4.50y − 35</span>
7 0
3 years ago
Read 2 more answers
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