Answer:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Step-by-step explanation:
Solve for b:
b - (3 + 2/5) = 8 + 1/5
Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:
b - (5×3)/5 + 2/5 = 8 + 1/5
5×3 = 15:
b - (15/5 + 2/5) = 8 + 1/5
15/5 + 2/5 = (15 + 2)/5:
b - (15 + 2)/5 = 8 + 1/5
15 + 2 = 17:
b - 17/5 = 8 + 1/5
Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:
(5 b)/5 - 17/5 = 8 + 1/5
(5 b)/5 - 17/5 = (5 b - 17)/5:
(5 b - 17)/5 = 8 + 1/5
Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:
(5 b - 17)/5 = (5×8)/5 + 1/5
5×8 = 40:
(5 b - 17)/5 = 40/5 + 1/5
40/5 + 1/5 = (40 + 1)/5:
(5 b - 17)/5 = (40 + 1)/5
40 + 1 = 41:
(5 b - 17)/5 = 41/5
Multiply both sides of (5 b - 17)/5 = 41/5 by 5:
(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 1/5×1/(1/5) 41
1/5×1/(1/5) = 1:
5 b - 17 = 41
Add 17 to both sides:
5 b + (17 - 17) = 17 + 41
17 - 17 = 0:
5 b = 41 + 17
41 + 17 = 58:
5 b = 58
Divide both sides of 5 b = 58 by 5:
(5 b)/5 = 58/5
5/5 = 1:
Answer: b = 58/5 or 11 3/5 or 11.6 decimal
Answer:
29 = 6 + k
k = 23
Step-by-step explanation:
The equation for that would be:
29 = 6 + k
and the answer would be:
29 = 6 + k
-6 -6
23 = k
k = 23
Answer:
24.6 < μ < 27.2
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.9 - 1.3 = 24.6 pounds.
The upper end of the interval is the sample mean added to M. So it is 25.9 + 1.3 = 27.2 pounds.
So the correct answer is:
24.6 < μ < 27.2
Y=9/4x-5 is the standard form.
