Answer:/?idk
Step-by-step explanation:
Answer:
(64+320π) cm^3
Step-by-step explanation:
The volume of a cube is the length*width*height, so
the volume of this cube is 4*4*4=64 cm^3
The volume of a cylinder is the base*height
The base of a cylinder is the area of a circle, which is π*the radius of the circle squared
The diameter of the circle base is 16, and the radius is half the diameter, so it is 16/2=8.
The area of the base of the cylinder is π8^2=64π
Now, multiply the base by the height, 5
64π*5=320πcm^3
We now have the volume of the cube and the volume of the cylinder, so now we just add them:
(64+320π) cm^3
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Answer:
x=-2.2 y=-1.6
Step-by-step explanation:
8x+y=-16
-3x+y=5
5x=-11
x=-11/5 or -2.2
-3x+y=5
-3(-2.2)+y=5
6.6+y=5
-6.6+y=-6.6
y=-1.6
1/3+3
Ab=1
-b^²=-9
B=3
A=1/3
a+b=1/3+3
Mark brainliest please
