Let

be the length of the rectangle and

be the width. In the problem it is given that

. It is also given that the area

. Substituting in the length in terms of width, we have

. Using the zero product property,

. Solving these we get the width

. However, it doesn't make sense for the width to be negative, so the width must be

. From that we can tell the length

.
Answer:
57 seconds
Step-by-step explanation:
55.7 + 1.3 = 57 seconds
The handshake problem!
Each of the five will play against 4 others, but since A vs B can be considered the same game as B vs A, so there are 5*4/2=10 matches.
Answer:C
Step-by-step explanation: