Answer:
D. Kingdom Fungi includes organisms that get energy by absorbing materials in their environment.
Explanation:
Organisms in the domain Eukarya are characterized by the possession of a well defined NUCLEUS in their cells. Kingdoms in this domain include animalia, plantae and fungi.
- Kingdom animalia contains multicellular organisms that are strictly heterotrophic i.e. cannot synthesize their own food, hence, rely on other organisms for nutrition.
- Kingdom plantae contains multicellular organisms that are capable of movement but not independently i.e. they cannot move from their fixed positions.
- Kingdom Fungi includes organisms that get energy by absorbing materials in their environment via a structure called MYCELIUM.
Combustion of Fossil Fuels
Explanation:
The combustion of fossil fuels is a major contributor to unbalancing of the carbon cycle which causes more carbon dioxide to be released into the air than can be naturally processed.
Combustion of fossil fuel is an anthropogenic source of carbon dioxide emission. This chemical process is used to power internal combustion engines and industrial activities. The by product is usually carbon dioxide.
Plants that use carbon dioxide for their life processes cannot completely absorb all of this anthropogenic emission.
Naturally, animal respiration and decomposition provides enough carbon dioxide for use during photosynthesis. Combustion of fossil fuels tips this balance.
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Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol = 
= 
= 
= 0.894 mol
Hence, number of moles of water = 
= 2.77
As glycol is dissolved in water.
So, the molality = 
= 17.9
Therefore, the expected freezing point = 
= 
Thus, we can conclude that the expected freezing point is
.
Answer:
A) a chain reaction that is caused by nuclear fission
Answer:
10.87 g of Ethyl Butyrate
Solution:
The Balance Chemical Equation is as follow,
H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH → H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O
According to equation,
88.11 g (1 mol) Butanoic Acid produces = 116.16 g (1 mol) Ethyl Butyrate
So,
8.25 g Butanoic Acid will produce = X g of Ethyl Butyrate
Solving for X,
X = (8.25 g × 116.16 g) ÷ 88.11 g
X = 10.87 g of Ethyl Butyrate