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FinnZ [79.3K]
2 years ago
6

Balance the following chemical equations.

Chemistry
1 answer:
Paul [167]2 years ago
8 0
A)Cu2O(s) + C(s) ———> 2Cu(s)+ CO(g)

B)H2(g) +Cl2(g)———> 2HCl(g)
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Answer: the object is transparent.

Explanation:

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3 years ago
When 3.18g of copper(ii)oxide was carefully heated in a stream of dry hydrogen, 2.54g of copper and 0.72g of water was formed. D
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7 0
3 years ago
A solution is prepared from 4.5701 g of magnesium chloride and 43.238 g of water. The vapor pressure of water above this solutio
balandron [24]

Answer:

i = 2.483

Explanation:

The vapour pressure lowering formula is:

Pₐ = Xₐ×P⁰ₐ <em>(1)</em>

For electrolytes:

Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ

Where:

Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)

4.5701g of MgCl₂ are:

4.5701g ₓ (1mol / 95.211g) = 0.048000 moles

43.238g of water are:

43.238g ₓ (1mol / 18.015g) = 2.400 moles

Replacing in (1):

0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm

0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)

2.4mol + i*0.048mol = 2.4mol / 0.9527

2.4mol + i*0.048mol = 2.5192mol

i*0.048mol = 2.5192mol - 2.4mol

i = 0.1192mol / 0.048mol

<em>i = 2.483</em>

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4 0
3 years ago
Please help I need this done!!
fenix001 [56]

I would get a container and weigh it. Then I would put the bouncy balls in the container and weigh it again. Then I would Subtract the weight of the container without the bouncy balls from the container with the bouncy balls.

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