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Hoochie [10]
3 years ago
13

Which one of these elements is the lightest: 1- oxygen , 2- carbon , 3- nitrogen , 4- neon.

Chemistry
1 answer:
icang [17]3 years ago
8 0
It would be carbon because its relative atomic mass is 12
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Pure substance A) Mixture that has its different components mixed evenly within the substance
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______________________ produce evidence that helps to answer important questions or could also lead to new questions.
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4 years ago
Chlorination of alkanes can produce a multitude of products. Determine the number of monochlorinated and dichlorinated products
ArbitrLikvidat [17]

Answer:

monochlorinated products: 4

dichlorinated products: 12

Explanation:

Chlorination of alkanes is a reaction that takes place when the chlorine is in presence of light. This actually decomposes the chlorine, and one atom of Chlorine substracts an hydrogen from the alkane. Now, this hydrogen substracted comes usually from the most substitued carbon, because it's more stable (A tertiary carbon is more stable than a secondary carbon, and this more stable than primary).

When this happens, the other chlorine atom, goes as electrophyle in that carbon and formed the chlorinated product. Now, although a tertiary carbon is more stable, we can still have (in minor quantities) chlorinated products that comes from a secondary and primary carbon. The first picture shows the general mechanism of the chlorination, and the possible products for a monochlorinated.

The second picture shows the possible dichlorinated products, which are in higher quantities than the monochlorinated basicallu because of the variety of positions the chlorine can be. So, second picture shows all the products.

6 0
4 years ago
Predict the major product of the following reaction of 1-methylcyclohexene with dilute HCl in H2O?
Scrat [10]

Answer:

1-chloro-1-methylcyclohexane

Explanation:

The hydrocarbons with one double bond are called alkenes and are named with the suffix "ene". The alkenes, such as 1-methylcyclohexene, react better in an addition reaction. The double bond will be broken, and the substitutes will be placed at them.

In the reaction with HCl, H and Cl will be added to the carbons of the broken bond. The major product is formed when H is put at the carbon less substituted. Thus, the product will be the one given below, 1-chloro-1-methylcyclohexane.

7 0
3 years ago
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