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slava [35]
3 years ago
5

How many moles are there in 3.9 grams of potassium

Chemistry
1 answer:
polet [3.4K]3 years ago
3 0

Answer:0.025576559594663 mole.

Explanation:

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Describe the physical and chemical weathering​
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Answer:

Physical weathering is caused by purely mechanical changes to the rock, while chemical weathering is caused by chemical reactions.

Explanation:

Chemical weathering happens when the chemicals get diluted and dissolved in water and seep and percolate down the rock surfaces.

Physical weathering happens when rocks are fragmented into minor fragments while ensuring no alterations in their chemical makeup. The main causes behind physical weathering include spontaneous fluctuations in temperature like too high or too low heat or cold

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3 years ago
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Question 3 When the population size decreases over time, the total number of births the total number of deaths. O less than O eq
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The population decreases when the birth rate is less than the death rate.
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2 years ago
What are two things required for something to be matter?
almond37 [142]
Atoms and particles
6 0
3 years ago
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Which of the following indicates that an exothermic reaction has taken place?
Tomtit [17]
<h2>Answer:</h2>

The option B is correct option. Which is release of heat and/or light energy .

<h3>Explanation:</h3>

According to the definition of exothermic reaction :

<em>An exothermic reaction is a chemical reaction that releases energy by light or heat.</em>

From definition option B (release of heat and/or light energy) indicates that an exothermic reaction has taken place.



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4 0
3 years ago
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Calculate the pH of a solution that is 0.235M benzoic acid and 0.130M sodium benzoate, a salt whose anion is the conjugate base
lesantik [10]

Hello!

We have the following data:

ps: we apply Ka in benzoic acid to the solution.

[acid] = 0.235 M (mol/L)

[salt] = 0.130 M (mol/L)

pKa (acetic acid buffer) =?

pH of a buffer =?

Let us first find pKa of benzoic acid, knowing that Ka (benzoic acid) = 6.20*10^{-5}

So:

pKa = - log\:(Ka)

pKa = - log\:(6.20*10^{-5})

pKa = 5 - log\:6.20

pKa = 5 - 0.79

\boxed{pKa = 4.21}

Now, using the abovementioned data for the pH formula of a buffer solution or (Henderson-Hasselbalch equation), we have:

pH = pKa + log\:\dfrac{[salt]}{[acid]}

pH = 4.21 + log\:\dfrac{0.130}{0.235}

pH = 4.21 + log\:0.55

pH = 4.21 + (-0.26)

pH = 4.21 - 0.26

\boxed{\boxed{pH = 3.95}}\end{array}}\qquad\checkmark

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR! =)

8 0
3 years ago
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