Round 132874015 to hype nearest hundreds thousand the digit to the right of the hundreds thousand is

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

Answer:

I think you meant to the nearest million because that is in the hundred millions not thousands but the answer is 100,000,000.

Step-by-step explanation:

If you did mean 100 thousands than your answer is 100,000.

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[Geometry] help pls!!!!<br><br> is the answer 70?

olga nikolaevna [1]

Notice the picture below

in a rectangle, all angles are 90 degrees and the diagonals are equal

meaning the diagonals bisect each other, they cut in equal halves

so. those two sides are equal, and thus they make up an isosceles triangle
on the sides

if those two sides are equal, the angles they make on the other side are equal

so if angle D is 55 degrees, angle A is 55 degrees
and the missing angle is 180 - (55 + 55) or 70
that's just the left-side

now, angle "x" on the right side, is a vertical angle of that angle on the left,
and vertical angles are equal, thus x = 70

4 0

3 years ago

Sixty percent means the same as _______.

ycow [4]

60% - 3/5
Hope this help, don't really know what your expecting the answer to be

3 0

3 years ago

I am simplifying radicals and I've come across one that has me a bit confused.

zhenek [66]

The sqrt of (34 m^4) is sqrt(34) times sqrt(m^4).

The sqrt of m^4 is easy ... that's just m^2 .

The other part is more messy. There's not much you can do with it.

sqrt(34) = sqrt(17) times sqrt(2).

That doesn't help make it any simpler.
You might as well just leave it as sqrt(34).

Then the final, simplified form of the original expression is

m^2 sqrt(34)

5 0

3 years ago

An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling

kondaur [170]

<h2>Hello! It will be a pleasure to help you! </h2><h2>So let's get started:</h2><h3 /><h2>PART 1. </h2><h3>An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling rate?</h3>

Sampling is simply a reduction of a continuous time signal to a discrete time signal. Here we know that an analogue sensor is sampled every $0.4ms$ to convert it into a digital representation. So sampling rate, also called the sampling frequency or $f_{s}$ , is the average number of samples obtained in one second, that is, samples per second:

$f_{s}=\frac{1}{T}$

Since we know:

$T=0.4ms$

Then, the sampling rate is:

$f_{s}=\frac{1}{0.4ms} \\ \\ f_{s}=2,500 \ samples \ per \ second \\ \\ Or: \\ \\ \boxed{f_{s}=2.5kS/s}$

<h3 /><h2>PART 2. </h2><h3>According to the Sampling Theorem, for this sampling rate value, what will be the highest frequency in the digital representation, assuming the lowest frequency in the sensor signal is very close to zero.</h3><h3 />

Sampling Theorem (Nyquist Theorem) States:

<em>A </em><em>continuous time signal </em><em>can be completely represented in its samples and recovered back, if the sampling frequency </em> $f_{s}$ <em>is greater than or equal to twice frequency component of the message signal.</em>

In other words:

$f_{s}\geq 2f_{m}$

So, the highest frequency in the digital representation will be:

$f_{m}=\frac{2500}{2} \\ \\ \boxed{f_{m}=1.25kHz}$

<h2>PART 3. </h2><h3>If each sample is quantised into 2048 levels, what will be the resulting bit-rate, giving your answer in scientific notation to 2 decimal places?</h3>

Everything is Ok up to this point! But let me explain something. We do all these things in order to get a faithful reproduction of the digital signal. So the Analog-to-Digital Conversion (ADC) allows us to do that.

In this final part, each sample is quantised to 2048 levels, so this number can be written as:

$2048=2^{11}$