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GenaCL600 [577]
3 years ago
5

What are the solutions to 6x^2-5x-4=0?​

Mathematics
1 answer:
enyata [817]3 years ago
6 0

Answer: x=−​1/2​​​​,​4/3

Step-by-step explanation:

1. Split the second term in 6x^2−5x−4 into two terms.

6x^2+3x−8x−4=0

2. Factor out common terms in the first two terms, then in the last two terms.

3x(2x+1)−4(2x+1)=0

3. Factor out the common term 2x+1.

(2x+1)(3x−4)=0

4. Solve for x.

Ask: When will (2x+1)(3x−4) equal zero?

When 2x+1=0 or 3x-4=0

Solve each of the 2 equations above.

x=−1/2,4/3

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