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svetlana [45]
3 years ago
15

Lucas used the number sentence 8 x 2 = 16 to solve a problem. Which problem could he have solved? ​

Mathematics
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

Word problem 3        

Step-by-step explanation:

Word Problem one is a subtraction problem since Felicia is giving away two marbles to Lucas. Word Problem two is a division problem since Felicia is evenly dividing the number of marbles she has into two bags. Word Problem three is a multiplication problem because Ryan has two times as many marbles that Felicia does. Word Problem four is an addition problem because she found two more marbles while she already has eight marbles. Keywords for subtraction word problems are: fewer than, decrease, take away, less than, minus, difference, change, lost reduced, and subtract. Keywords for division word problems are: As much, cut up, groups, equally, sharing, half, how many in each, parts, per percent, quotient, ratio, and separated. Keywords for multiplication word problems are: double, every, factor, increased, multiplied product, times, and tripled.

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According to Confucianism, what is the government’s most important role in society?
nadya68 [22]
C because one they would provide food and possibly anything to help people out
3 0
3 years ago
Read 2 more answers
lin has 8 green apples and 2 red apples .if he slices the green apples in eighths ,how many apple slices will he have ?
lutik1710 [3]
64 because each apple is sliced into 8ths and there are 8 apples so 8x8=64
3 0
3 years ago
Julio bought 4 pencils and 3 erasers for $0.37 and David paid $0.33 for 3 pencils and 4 erasers. What is the cost of one pencil?
grigory [225]

cost of pencil = x = 0.07

and cost of eraser = y = 0.03

Step-by-step explanation:

let cost of pencil = x

and cost of eraser = y

So, we have equations:

4x+3y=0.37\\3x+4y=0.33

Solving both equations to find value of x and y

Let:

4x+3y=0.37\,\,\,eq(1)\\3x+4y=0.33\,\,\,eq(2)

Multiply eq(1) with 4 and eq(2) with 3 and subtract

16x+12y=1.48\\9x+12y=0.99\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-\\--------\\7x=0.49\\x=0.07

Putting value of x in equation 1:

4x+3y=0.37\\4(0.07)+3y=0.37\\0.28+3y=0.37\\3y=0.37-0.28\\3y=0.09\\y=0.03

So, x= 0.07 and  y = 0.03

cost of pencil = x = 0.07

and cost of eraser = y = 0.03

Keywords: System of equations

Learn more about system of equations at:

  • brainly.com/question/9045597
  • brainly.com/question/3739260
  • brainly.com/question/13168205

#learnwithBrainly

4 0
3 years ago
3=c/5+2... how do I solve for c??
expeople1 [14]
Primeiro Você IRA Dividir o c (APENAS Colocar 5 + 2 embaixo do c). Depois faça a soma 5 + 2 = 7. Então faça o mmc (mínimo múltiplo comum) entre 7 e 1(o 1 é invisível, mas continua estando embaixo do 3). Deu 7 o mmc. Transforme seus números em frações, com o denominador 7. Transforme os números em frações o 3 virá 21, pois você divide em baixo e multiplica em baixo, e o c continua normal, pois já estava em baixo de 7. Como é para descobrir uma incógnita você tira os denominadores e ficará 21 = c.

3 = c/5 + 2
3 = c/7
21/7 = c/7
21 = c
4 0
3 years ago
Read 2 more answers
Jocelyn owns a food truck that sells tacos and burritos. She only has enough supplies to make 150 tacos or burritos. She sells e
timurjin [86]

Answer:

We know that:

Price of a taco = $4

Price of a burrito = $6.50

x = number of tacos sold

y = number of burritos sold.

We must have that:

x + y ≤ 150  (Because she only has supplies to make 150 tacos or burritos, but she can sell less than that)

And also we know that she must sell at least $780, then:

x*$4 + y*$6.50 ≥ $780

Now we found the system of inequalities:

x + y ≤ 150

x*$4 + y*$6.50 ≥ $780

To solve it graphically, we just need to find each one of the region solutions for each equation, and the intersection of these regions will be the solution for the system.

To graph them may be easier to write them as lines, you can do it as follows:

y ≤ 150 - x

y ≥ ($780 - x*$4)/$6.50

in the first equation, we will shade the area below the line, and in the second equation, we will shade the area above the line.

You can see the image below.

Where the accepted solutions are the ones in the darker part, and we only restrict this to positive values of x (because of how we defined the variable x)

Then looking at the image, we can see that one solution can be the point

x = 20, y = 120

7 0
3 years ago
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