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GaryK [48]
3 years ago
5

Can somebody help n explain ​

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

A) 32

Step-by-step explanation:

I will assume the function is

f(x) = 32 (1.5)^x

This is in the form

y =a b^x

in which a is the initial value, b is the growth rate, x is the time

a =32, which is the initial population

b= 1.5, which means 1.5-1 = .5. which means it grows at a 50% increase

x = number of  years

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Which quadrant will the line y=Negative one-fourthx – 15 never pass through?
Nata [24]

Answer:

quadrant 2

Step-by-step explanation:

6 0
3 years ago
Can anyone help me please?
miss Akunina [59]

Answer:

  5. -18x^3y^4 +54x^2y^4

  6. 6x^2 -40x +50

Step-by-step explanation:

Use the distributive property. The factor outside parentheses multiplies each term inside parentheses.

__

<h3>5.</h3>

  (9xy)(-2x^2y^3+6xy)=(9xy)(-2x^2y^3)+(9xy)(6xy^3)\\\\=\boxed{-18x^3y^4+54x^2y^4}

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<h3>6.</h3>

  (3x-5)(2x-10)=3x(2x-10)-5(2x-10)\\\\=6x^2-30x-10x+50=\boxed{6x^2-40x+50}

7 0
2 years ago
What is the value of x in the equation below?
belka [17]
remember
ln(a^b)=bln(a)
ln(e)=1
so
ln(e^x)=xln(e)=x


1+2e^{x+1}=9
minus \space\ 1 \space\ both \space\ sides
2e^{x+1}=8
divide \space\ both \space\ sides \space\ by \space\ 2
e^{x+1}=4
take \space\ ln \space\ of \space\ both \space\ sides
ln(e^{x+1})=ln(4)
(x+1)ln(e)=ln(4)
x+1=ln(4)
minus \space\ 1 \space\ from \space\ both \space\ sides
x=ln(4)-1
answer \space\ is \space\ C=ln(4)-1
5 0
3 years ago
Read 2 more answers
Solve the equation : |x| - 6 = 4
wlad13 [49]

Answer:

x=10

Step-by-step explanation:

10-6 is equal to 4. The absolute value of 10 is 10. Therefore, x=10. Brainliest?

6 0
3 years ago
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

= $6,240

Hence,

The correct answer is option (a) $6,240

7 0
3 years ago
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