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3 years ago

11

Point B is between points A and C. Find the length of AC if AB = 3x - 2, BC = 2x + 7 and AC = 4x + 10

1 answer:

kirill115 [55]3 years ago

3 0

Answer:

AC = 30

Step-by-step explanation:

Start with:

$4x+10=3x-2+2x+7$

Combine like terms.

$4x+10=5x+5$

Subtract $4x$ from both sides of the equation.

$10=x+5$

Subtract $5$ from both sides of the equation.

$x = 5$

Then, substitute $5$ for $x$ in $AC=4x+10$

$AC=4(5)+10$

Multiply.

$AC=20+10$

Finally, add.

$AC=30$

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Juli2301 [7.4K]

Times 175×3=525-175=300

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If Sheila paid $797.50 in interest on a 5 year loan of $5,800 for her first car, what was the interest rate? (Make sure you’ve c

Vsevolod [243]

I = Prt
r = I/Pt
given
I = <span>$797.50
P = </span><span>$5,800
t = 5

so
</span>r = I/Pt
r = 797.50 / (5,800 x 5)
r = 797.50 / 29,000
r = 0.0275
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answer
r = 2.75%

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3 years ago

Read 2 more answers

Maria can type 25 words per minute while Amanda can type 30 words per minute. Maria was already typing for 12 minutes when Amand

tekilochka [14]

The answer would be 10

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3 years ago

Si: Tg θ =√2 ∧ θ es agudo √7 Calcular: A = 3(Sen θ + Cos θ) - √7

Harlamova29_29 [7]

Answer:

$A \approx 1.488$

Step-by-step explanation:

Por definición de razones trigonométricas, tenemos las siguientes identidades:

$\tan \theta = \frac{y}{x} = \sqrt{2}$ (1)

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$ (2)

$\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}$ (3)

Si $\theta$ es agudo, entonces $x, y > 0$ .

De (1), suponemos $x = 1$ que $y = \sqrt{2}$ , entonces los valores de las funciones seno y coseno:

$\sin \theta = \frac{\sqrt{2}}{\sqrt{5}} = \sqrt{\frac{2}{5} }$

$\sin \theta = \frac{\sqrt{10}}{5 }$

$\cos \theta = \sqrt{\frac{1}{5} }$

$\cos \theta = \frac{\sqrt{5}}{5}$

Por último, calculemos $A$ :

$A = 3\cdot \left(\frac{\sqrt{10}}{5} + \frac{\sqrt{5}}{5} \right) - \sqrt{7}$

$A \approx 1.488$

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kotegsom [21]

Answer:

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Step-by-step explanation:

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