An ______ is a simplified image. [4 letters]

How long will the plant have been dead when 87.5 percent of its C-14 has become N-14?

nikdorinn [45]

Answer:

50% - one half life — 5,730 years

25% — two half lifes — 11,460 years

12.5% — three half lifes — 17,190 years

6.25% — four half lifes — 22,920 years

3.125% — five half lifes — 28,650 years

Explanation:

8 0

2 years ago

Which algorithm makes the most efficient use ofmemory?

SashulF [63]

Answer:

Best-fit Algorithm

Explanation:

Best-fit: Allocating the smallest memory location that is greater than or equal to the size of process.

Example

Let these are the memory locations-210kb,310kb,260kb,610kb

and size of processes-160kb,450kb,250kb,300kb

For the first-fit,

We allocate 160 kb to the 210kb memory location

Then, we allocate 450 kb to the 610kb because others don't have the size.

Then,we allocate 250kb to the 310 kb.

300 kb will stop,as no memory locations can execute.

For the Best-fit,

We allocate 160 kb to the 210kb memory location

Then,we allocate 450kb to the 610kb.

Then,we allocate 250kb to the 260kb not 310kb according to best-fit.

Then we allocate 300kb to the 310kb.

For the worst fit,

We allocate 160 kb to the 610kb memory location according to the worst-fit algorithm.

Then,we can't allocate 450kb to any memory location.

Then,we allocate 250kb to the 310kb .

We can' allocate 300kb in 260kb memory location.

As we can see from this example that in First-fit algorithm 300kb process will stop as no memory location is there.

In worst-fit algorithm ,We can't allocate 450kb,300kb to any memory locations.

In Best-fit algorithm,we can allocate the process to each location,so this algorithm is using memory in a efficient way.

5 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Use the following scale to rate yourself: (There is no wrong answer

Law Incorporation [45]

Doesnt have any picture

8 0

2 years ago

Your car's engine, transmission, power steering, and brakes all require __________ inspection and changes.

kvasek [131]

The answer is C

All parts require fluid

4 0

3 years ago

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An ______ is a simplified image. [4 letters]​

An ______ is a simplified image. [4 letters]