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Nata [24]
3 years ago
11

4. 15 Exact change (College level not sure why it says middle school)

Computers and Technology
1 answer:
sweet [91]3 years ago
6 0

Answer:

def print_change(total_change):#this is also total cents, because integers don't have decimal points, so I can't use dollars as my unit

dollars = int(total_change / 100)

remaining_change = total_change - dollars * 100

quarters = int(remaining_change / 25)

remaining_change -= quarters * 25

dimes = int(remaining_change / 10)

remaining_change -= dimes * 10

nickels = int(remaining_change / 5)

remaining_change -= nickels * 5

pennies = remaining_change

all = {'dollar': dollars, 'quarter': quarters, 'dime': dimes, 'nickel': nickels, 'penny': pennies}

for num in [0, 1, 2, 3, 4]:

coin_type = list(all.keys())[num]

amount = all[coin_type]

if num < 4 and amount > 1 or amount == 0 and num < 4:

coin_type += 's'

elif num == 4 and amount > 1 or amount == 0 and num == 4:

coin_type = 'pennies'

print('\n', amount, coin_type)

while True:

total_change = int(input()) #in cents

print_change(total_change)

Had fun making this one... hope it helps. :)

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4G/5G.

Explanation:

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3 years ago
Hello everyone. I need help. C programming. Create at least two more functions except the main () function to collect them.
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Answer:

Explanation:

#include <iostream>

using namespace std;

int costdays(int);

int costhrs(int,int);

int main()

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   int dd,hh,mm,tmph,tmpd,tmpm=0;

   int pcost,mcost=0;

   cout<<"Enter Parking time" << endl;

   cout<<"Hours: ";

   cin>>hh;

   cout<<"Minutes: ";

   cin>>mm;

   

   if (mm>60)

   {

       tmph=mm/60;

       hh+=tmph;

       mm-=(tmph*60);

   }

   if (hh>24)

   {

       tmpd=hh/24;

       dd+=tmpd;

       hh-=(tmpd*24);

   }

   if ((hh>4)&&(mm>0))

   {

       pcost+=costdays(1);

   }

   else

   {

       mcost=costhrs(hh,mm);

   }

   cout<<"Total time: ";

   if (dd>0)

   {

       cout<<dd<<"days ";

       pcost+=costdays(dd);

   }

   pcost+=mcost;

   cout<<hh<<"h "<<mm<<"mins"<<endl;

   cout<<"Total Cost :"<<pcost<<"Won";

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}

int costdays(int dd)

{

   return(dd*25000);

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   int tmpm, tmp=0;

   tmp=(hh*6)*1000;

   tmp+=(mm/10)*1000;

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4 years ago
Define a method printFeetInchShort, with int parameters numFeet and numInches, that prints using ' and " shorthand. End with a n
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Answer:

The program to this question as follows:

Program:

//header file

#include <iostream> //defining header file

using namespace std;

void printFeetInchShort(int numFeet,int numInches); //decalring method printFeetInchShort  

void printFeetInchShort(int numFeet,int numInches)//defining method printFeetInchShort

{

cout<<"height: "; // print message

cout<<numFeet<<"\'"<<""<<numInches<<"\""; //print value

}

int main() //defining main method

{

int numFeet, numInches; //defining integer variable

cout<<"Enter height feet: "; //print message

cin>>numFeet; //input value by user

cout<<"Enter height inches: "; //print message

cin>>numInches; //input value by user

printFeetInchShort(numFeet,numInches); //calling method printFeetInchShort    

return 0;

}

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Enter height inches: 9

height: 5'9"

Explanation:

In the above C++ language program, first, a header file is included, that uses the basic function, in the next step, the "printFeetInchShort()" method is defined, in the method two integer variables passed as a parameter, inside this method a print function "cout" is used, that print user input value with single and double quote.

Then the main method is declared, inside this method two integer variables "numFeet and numInches" are defined, which is used to take input value by user and pass the value in "printFeetInchShort()" function parameter and call the function.

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