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mylen [45]
3 years ago
8

What’s the point slope form of an equation the has a slope of: (-1/6)

Mathematics
1 answer:
Zolol [24]3 years ago
5 0

Answer:

  • y +4 = (-1/6)(x -9)
  • y = -1/6x -2.5

Step-by-step explanation:

The point-slope form of the equation for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

For your given values m=-1/6 and (h, k) = (9, -4), your equation is ...

  y +4 = (-1/6)(x -9)

__

Solving for y puts this in slope-intercept form.

  y = -1/6x +9/6 -4 . . . . eliminate parentheses, subtract 4

  y = -1/6x -2.5

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Answer:

EXACTLY. People need to understand we are using this because we need help, we don't wanna about your personal life and gross stuff.

3 0
3 years ago
Marco got a quotient of 70 when he divided 49 by 0.07.
solniwko [45]
The correct answer for this problem is 700. This is because 0.07 is in the hundredths place. Marco got it wrong because he didn't count the place correctly. 
5 0
3 years ago
HELP. ASAP. EASY MUTIPLE CHOICE QUESTIONS.<br>​
Alina [70]

Answer:

C 44.59

Step-by-step explanation:

The first two shirts are full price

2*49.96 = 99.92

The third shirt is 50% off.  That means it is 50% of the original price

.5*49.96 = 24.98

The total cost before tax is

99.92+24.98 =124.90

tax = cost * tax rate

tax = 124.90*.071

tax=8.87

Add this to the cost

final cost = 124.90+8.87

                =133.77

We want to find the mean cost (average cost)

Take the total cost and divide by the number of shirts

133.77/3 =44.59

5 0
3 years ago
Read 2 more answers
F(x)=1/2×+6 plz helpppppppppp​
FromTheMoon [43]

Answer:

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

Step-by-step explanation:

Given function:

f(x)=\frac{1}{2x+6}

To find the domain of the function in set notation.

Solution:

For the function f(x) to exist the denominator must be ≠ 0

We have the denominator (2x+6) which  cannot be = 0.

Thus, we can find the domain of the function using the above relation.

The function f(x) will not exist when:

2x+6=0

Solving for x

Subtracting both sides by 6.

2x+6-6=0-6

2x=-6

Dividing both sides by 2.

\frac{2x}{2}=\frac{-6}{2}

∴ x=-3

Thus, the function will not exist at x=-3. This means it has all real number solutions except -3.

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

3 0
3 years ago
Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values
Vesnalui [34]

The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

4 0
2 years ago
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