Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm

8 0

3 years ago

Help if your gonna answer plz explain it

Katyanochek1 [597]

So you wanna find the area of each surface:

For the large square surface in the top you do 12*15=180 and there are two large squares faces so you multiply 180 by 2 which equals 360 then you find the small rectangle faces: 5*15=75 and multiply by 2 Bc there are 2 faces like that so it would be 75*2=150 then for the last faces you do 12*5= 60 *2= 120 at the end I add all of the faces up, 360+150+120=630

6 0

3 years ago

Help ASAp peaseeeeeeeeee

PIT_PIT [208]

Answer:

7/6

Step-by-step explanation:

$\frac{ \frac{x}{4} + \frac{x}{3} }{ \frac{x}{2} } = \frac{x( \frac{1}{4} + \frac{1}{3} )}{ x(\frac{1}{2}) } \\ = \frac{ \frac{1}{4} + \frac{1}{3} }{ \frac{1}{2} } \\ = \frac{14}{12} = \frac{7}{6}$

3 0

2 years ago

Read 2 more answers

Leanne has a gas card that has $150 on it. She spends $25 a week on gas. Write and recursive rule that represents the amount of

Tems11 [23]

In this question, it is given that

Leanne has a gas card that has $150 on it. She spends $25 a week on gas.

And we have to Write a recursive rule that represents the amount of money she has on her gas card after the first week .

Recursive rule shows the relationship between previous value and the current value .

And here, the recursive rule is

$a_{n} = a_{n-1}-25n$

Where a(n-1) is the initial amount which is $150 . And a(n) is the amount after n week .

So for n=1, that is amount in the card after 1 week, we will get

$a_{1} = a_{1-1} -25(1)
\\
a_{1} = a_{0} -25
\\
a_{1} = 150 -25
\\
a_{1} = $125$

And that's the amount remaining in the card after 1 week .

5 0

3 years ago