If
<em>f(x)</em> = <em>ax</em> ³ + <em>bx</em> ² - 5<em>x</em> + 9
then
<em>f '(x)</em> = 3<em>ax </em>² + 2<em>bx</em> - 5
Given that <em>f</em> (-1) = 12 and <em>f</em> '(-1) = 3, we get the system of equations
-<em>a</em> + <em>b</em> + 5 + 9 = 12
3<em>a</em> - 2<em>b</em> - 5 = 3
or
-<em>a</em> + <em>b</em> = -2
3<em>a</em> - 2<em>b</em> = 8
Multiply through the first equation by 2 and add it to the second one to eliminate <em>b</em> and solve for <em>a</em> :
2(-<em>a</em> + <em>b</em>) + (3<em>a</em> - 2<em>b</em>) = 2(-2) + 8
-2<em>a</em> + 2<em>b</em> + 3<em>a</em> - 2<em>b</em> = -4 + 8
<em>a</em> = 4
Substitute this into the first equation above to solve for <em>b</em> :
-4 + <em>b</em> = -2
<em>b</em> = 2
1/3 chance of getting a cracked egg
Since it's y/x, and x is what you input into the function (and y is what you get out), we get that the amount donated is based off of the lunch specials, so we get y(12)/x(60)=12/60=1/5Since it's y/x, and x is what you input into the function (and y is what you get out), we get that the amount donated is based off of the lunch specials, so we get y(12)/x(60)=12/60=1/5.
Answer:
Step-by-step explanation:
x² - 144 = x² - 12²
= (x +12)(x - 12)
a² - b² = (a + b)(a-b)
x = 5y - z
You can think that x and z are numbers, and we have one variable z.
x -5y = 5y - 5y - z
x - 5y = - z
(x - 5y)*(-1) = - z *(-1)
z = - x + 5y
