Simplify the expression: 9f+10(

Neal's decision is to fail to reject the null hypothesis (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all Ledee household is greater than , 854.28 kWh

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 854.11$

The sample size is $n = 65$

The sample mean is $\= x = 879.28 \ kWh$

The standard deviation is $\sigma = 133.29 \ kWh$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o: \mu = 854.11$

The alternative hypothesis is $H_a : \mu > 854.11$

The t-statistics is $t = 1.522$

The p-value is $p-value = 0.066$

Now from the given data we can see that

$p-value < \alpha$

Generally when this is the case , we fail to reject the null hypothesis

So

Neal's decision is to fail to reject the null hypothesis (p 0.066). There is no sufficient evidence to prove the claim that the average electricity consumption of all Ledee household is greater than , 854.28 kWh