It variates depending on the significant of x
Make a table with the angle theta as independent variable and the radius r as dependent variable:
theta radius = 4+2cos theta radius
------- -----------------------------------------
0 4+2 6
pi/6 4+2cos pi/6 = 4+2(sqrt(3)/2
Perhaps you have already plotted this using webassign (but remember that you have not shared an illustration here). (Please don't type "webassign plot" repeatedly, as it accomplishes nothing.)
Generally, when one wishes to find the area of a region defined by polar functions (as is the case here), one first determines suitable limits of integration from the finished curve and checks them through actual integration.
Which formula should you use to find the area: Look up "areas in polar coordinates," as I did. The formula is as follows:
Enclosed area = Integral from alpha to beta of (1/2)r^2 d(theta). Note that the initial radius here is 6 (since r = 4 plus 2 cos theta is 4+2 when theta = 0).
Hum, seems to subtract 9 then subtract 15 then subtract 21
the amount subtracted increases by 6 each time
so then we subtract 27 to get -59
then subtract 33 to get -92
the next two terms are -59 and -92
Answer:
5.99 per pair
Step-by-step explanation:
Take the cost of the package and divide by the number of pairs
29.95/5
5.99
Each pair costs 5.99
