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KonstantinChe [14]
3 years ago
6

Point A has the coordinates (6, –4). On a coordinate plane, point R is 6 units to the left and 4 units up. Point S is 6 units to

the right and 4 units down. Point T is 6 units to the left and 4 units down. Point U is 6 units to the right and 4 units up. Which point on the graph shows the reflection of point A across the y-axis? R S T U
Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

The point T shows the reflection of point A across the y-axis

Step-by-step explanation:

we know that

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite

so

The reflection of a point across the y-axis is equal to the rule

(x,y) -----> (-x,y)

we have

A(6,-4)

Applying the reflection across the y-axis to point A

A(6,-4) -----> A'(-6,-4)

Remember that

Point T is 6 units to the left and 4 units down

therefore

The point T shows the reflection of point A across the y-axis

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Step-by-step explanation:

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3 0
3 years ago
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If EF=2x-12, FG= 3x-15, and EG=23, find values of x, EF, and FG
velikii [3]

we have that


*-------------------------*--------------------------------*

E                            F                                     G


EF=2x-12

FG= 3x-15

EG=23


we know that


EF + FG = EG


so

[2x - 12] + [3x - 15] = 23 simplify

5x - 27 = 23 add 27 to both sides

5x = 50 divide both sides by 5

x = 10

EF=2x-12-------> EF=2*10-12-------> EF=8

FG= 3x-15------> FG=3*10-15------> FG=15



therefore


the answer part a) is

the value of x is 10


the answer part b) is

the value of EF is 8


the answer part c) is

the value of FG is 15

6 0
3 years ago
If f'(0) = 5 and F(x) = f(3x), what is F'(0)?
Llana [10]

Answer:

\displaystyle F'(0) = 15

Step-by-step explanation:

We are given that:

f'(0) = 5 \text{ and } F(x) = f(3x)

And we want to find F'(0).

First, find F(x):

\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]

From the chain rule:

\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}

Then:

\displaystyle \begin{aligned} F'(0) & = 3f'(3(0)) \\ \\ & = 3f'(0) \\ \\ & = 3(5) \\ \\ & = 15\end{aligned}

In conclusion, F'(0) = 15.

7 0
2 years ago
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Part A
Ber [7]

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Step-by-step explanation:

Lol

7 0
2 years ago
Solve (-6 - 4)÷(-5) =
Vinil7 [7]

-6-4=-10

-10/-5=2

so 2 is ur answer

4 0
3 years ago
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