She will get 23 books.
So, first, you take the shipping away to get $93.05,
then you divide $93.05 by $3.95 which equals 23.55
and you can't have half a book; so it's 23!
Answer: √117
Step-by-step explanation:
Since no diagram present, am assuming hypotenuse AB and right angle C. Let side opp angle B be b, and side opposite angle A be a. Altitude CD is x.
a^2 + b^2 = 22^2 (Pythagorean)
Using Pythag on two smaller triangles,
x^2 + 13^2 = a^2
x^2 + 9^2 = b^2
Substituting in first equation,
x^2 + 13^2 + x^2 + 9^2 = 22^2
x^2 = 117, so x = √117
Answer:
C) √5(cos(117°) +i·sin(117°))
Step-by-step explanation:
The rectangular number a+bi can be written in polar form as ...
√(a^2+b^2)×(cos(arctan(b/a)) + i·sin(arctan(b/a)))
Here, we have a=-1, b=2, so the magnitude is ...
√((-1)^2 +2^2) = √(1+4) = √5
and the angle is ...
arctan(2/(-1)) = arctan(-2) ≈ 116.565° . . . . . a 2nd-quadrant angle
Then you have ...
-1 +2i = √5(cos(117°) +i·sin(117°)) . . . . . . customary "polar form"
_____
Comment on the answer
The "polar form" is generally written as ...
(magnitude)·(cos(angle) +i·sin(angle))
You may also see it as ...
(magnitude) cis (angle) . . . . . . . where "cis" is shorthand for "cos + i·sin"
In my engineering courses, we often used the form ...
(magnitude) ∠ (angle)
The form used by my calculator is ...
(magnitude)·e^(i·angle) . . . . . where angle is usually in radians
Answer:
the area is 735
Step-by-step explanation:
using the fomular 1/2(the base *the height you solved for the area
