Ask question

Ask question

All categories

3 years ago

14

The ____ contains buttons that provide different views of the document window, and some common operations related to viewing and

managing the document.

Computers and Technology

1 answer:

alexandr402 [8]3 years ago

8 0

I think it is called a document tool bar

You might be interested in

Discussion Six: Code of Ethics IT workers have many different relationships, including those with employers, clients, suppliers,

tia_tia [17]

An ethical issue that IT organizations face today is that of being able to illegally download software or files that should not be legally available, or that should not be downloaded for free. This poses an ethical problem, as dowloading these items illegally would greatly benefit the IT company economically. However, the company is required to ignore the availability of such material and instead abide by the law.

An example of this in my personal life is that of dowloading illegal music. As I am aware of the fact that dowloading music for free from illegal sites is against the law, I have taken the responsibility of not doing it. However, this requires me to control or moderate my behaviour, as I know that I have the skills and the financial incentive to act in this way. I have to remember that, although I have the skills to do so, I do not have the right to abuse the systems or the data that I have access to.

5 0

3 years ago

Julli [10]

Answer:

Following are the code to the given question:

#include<iostream>//header file

#include<math.h>//header file

using namespace std;

int main()//main method

{

long long x, x1, y, y1;//defining long variable

int count=0,i,j;//defining integer variable

cout<<"Enter a range for x coordinates: "<<endl;//print message

cin>>x>>x1;//input x and x1 value

cout<<"Enter a range for y coordinates: "<<endl;//print message

cin>>y>>y1; //input y and y1 value

for(i = x; i <= -x1; i++)//use nested loop that tests each coordinates

{

for(j = y; j <= y1; j++)//use nested loop that tests each coordinates

{

if(((2*pow(i,2)) + abs(2*i*j) + pow(j,2)) == 10000)//use if that checks condition as per the given question

{

cout<<"There is a planet at "<<i<<", "<<j<<endl;// print coordinates

count++;//incrementing count variable value

}

}

}

cout<<"Total number of planets detected are: "<<count<<endl;//print count value

return 0;

}

Explanation:

In this code, inside the main method long "x, x1, y, and y1" and integer "count, i, and j" type variable is declared that uses a long variable to input value from the user-end.

In the next step, two nested loops have defined that test each coordinate and define if block that checks condition as per the given question and use i, j, and count variable to print value with the message.

3 0

3 years ago

The field that uses technology to manipulate and use information to improve healthcare is known as:_______

Sergeu [11.5K]

Answer:

Health informatics

Explanation:

7 0

2 years ago

MyProgramming Lab

Akimi4 [234]

Answer:

Explanation:

The following code is written in Python. It creates a method for each one of the questions asked and then tests all three with the same test case which can be seen in the picture attached below.

def alternating_list(lst1, lst2):

lst3 = []

for x in range(len(lst1)):

lst3.append(lst1[x])

try:

lst3.append(lst2[x])

except:

pass

if len(lst2) > len(lst1):

lst3.extend(lst2[len(lst1):])

return lst3

def reverse_alternating(lst1, lst2):

lst3 = []

if len(lst1) == len(lst2):

for x in range(len(lst1) - 1, -1, -1):

lst3.append(lst1[x])

lst3.append(lst2[x])

return lst3

def alternating_list_no_extra(lst1, lst2):

lst3 = []

max = 0

if len(lst1) > len(lst2):

max = len(lst2)

else:

max = len(lst1)

for x in range(max):

lst3.append(lst1[x])

try:

lst3.append(lst2[x])

except:

pass

return lst3

4 0

3 years ago

CHALLENGE ACTIVITY 4.2.2: Basic while loop with user input. Write an expression that executes the loop while the user enters a n

tino4ka555 [31]

Answer:

#include<iostream>

using namespace std;

int main()

{

int userNum;

userNum=9;

while(userNum>=0)

{

cout<<"Body"<<endl;

cin>>userNum;

}

cout<<"Done"<<endl;

return 0;

}

Explanation:

Use the userNum >= 0 expression that executes the loop while the user enters a number greater than or equal to 0.
Print the userNum inside the while loop.

3 0

3 years ago