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Helen [10]
3 years ago
5

Please help

Chemistry
1 answer:
Colt1911 [192]3 years ago
3 0
A i belive is the correct answer

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Murcury is the only metal at room temperature. Its density is 13.6g/mL. How many grams of murcury will occupy a volume of 95.8mL
Hatshy [7]

Answer:

<h3>The answer is 1.30288 × 10³ g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 95.8mL

density = 13.6g/mL

We have

mass = 13.6 × 95.8 = 1302.88

We have the final answer as

<h3>1.30288 × 10³ g</h3>

Hope this helps you

3 0
3 years ago
What data do you need to determine the specific heat capacity of a substance?
strojnjashka [21]

Speific heat capacity is measured with the aid of determining how a whole lot warmth electricity is needed to increase one gram of a substance one digree Celsius. The Speific heat capacity of water is 4.2 joules per gram per degree Celsius or 1 calorie in step with gram per digree Celsius.

The specific heat capacity is defined as the amount of heat (J) absorbed consistent with unit mass (kg) of the substance while its temperature increases 1 ok (or 1 °C), and its units are J/(kg k) or J/(kg °C).

Factors specific heat capacity relate to are temperature and strength.

The Speific heat capacity C can be measured as q = mC∆T

Or, C = q/m∆T

where,

C is the specific heat capacity

q is the quantity of heat required

m is the mass

∆T is the change in temperature

As a consequence so as to degree the specific heat capacity we need to recognize mass of the substance, quantity of heat lost or gain by the substance and the exchange in temperature.

Lear more about Speific heat capacity here: brainly.com/question/17162473

#SPJ4

6 0
1 year ago
Consider the reaction: I2(g)+Cl2(g)⇌2ICl(g) Kp= 81.9 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each condition: -
scoray [572]

Answer:

Part 1: - 1.091 x 10⁴ J/mol.

Part 2: - 1.137 x 10⁴ J/mol.

Explanation:

Part 1: At standard conditions:

At standard conditions Kp= 81.9.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(81.9)) = - 1.091 x 10⁴ J/mol.

Part 2: PICl = 2.63 atm; PI₂ = 0.324 atm; PCl₂ = 0.217 atm.

For the reaction:

I₂(g) + Cl₂(g) ⇌ 2ICl(g).

Kp = (PICl)²/(PI₂)(PCl₂) = (2.63 atm)²/(0.324 atm)(0.217 atm) = 98.38.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(98.38)) = - 1.137 x 10⁴ J/mol.

6 0
3 years ago
Read 2 more answers
To begin the experiment, 1.11g of methane CH4is burned in a bomb calorimeter containing 1000 grams of water. The initial tempera
navik [9.2K]
1. CH4 + 2O2 → CO2 + 2H2O
2. 10.80 degrees celsius
3. 45,187 J
4. 7,506 J
<span>5. 52,693 J </span>
6 0
3 years ago
Question 38 (1 point)
Fiesta28 [93]

Answer: Protons because they have a positive charge.

Explanation:

8 0
3 years ago
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