Answer:
answer: they seek to produce verficiable data.
Answer:
umm ok lol thx for the f r e e points
<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %
<u>Explanation:</u>
We are given:
Mass of hydrogen = 7 grams
Mass of nitrogen = 32 grams
Mass of carbon = 7 grams
Total mass of the sample = 7 + 32 + 7 = 46 grams
To calculate the percentage composition of hydrogen in sample, we use the equation:

Mass of sample = 46 g
Mass of hydrogen = 7 g
Putting values in above equation, we get:

Hence, the percent composition of hydrogen in the sample is 15.22 %
Answer:
Explanation:
a. What is the mass number of the particle emitted from the nucleus during beta minus (β–) decay?
zero
The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.
⁴₆C → ¹⁴₇N + ⁰₋₁e
b. What kind of charge does the particle emitted from the nucleus during beta minus (β–) decay have?
Negative charge
Electron is emitted during beta decay and it carry negative charge.
c. What is another name for a beta minus (β–) particle?
Electron
During beta minus decay electron is emitted and neutron is converted into proton.
d. Write the balanced equation for the alpha decay that is below the “Show Equation.” Label the parent, daughter, and beta particle.
Equation is missing
a. What happens in the nucleus of an atom when an alpha particle is emitted?
When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4 and atomic number less than 2 as compared to the starting atom.
b. b. What happens in the nucleus of an atom when a beta particle is emitted?
When nucleus emit the beta particle neutron is converted into proton and this proton stay into the nucleus while at the same time electron is emitted. Thus atomic number is increased by one.
⁴₆C → ¹⁴₇N + ⁰₋₁e
The reaction is incorrect. The correct reaction is: Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃. The options are:
A. Hg₂SO₄
B. Na₂SO₄
C. Na⁺
D. NO₃⁻
E. SO₄⁻²
F. Hg₂(NO₃)₂
G. NaNO₃
H. Hg⁺²
Answer:
C, D, E, H
Explanation:
The ions are formed after dissociation of the compound in the solution. When they're negatively charged, they're called anions, when they're negatively charged, they're called cations. If the ion is presented on both sides of the reaction, it is called a spectator ion.
Thus, the reaction given:
Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃
So, let's do the dissociation.
Na₂SO₄ is formed by the ions Na⁺ and SO₄⁻²;
Hg(NO₃)₂ is formed by the ions Hg⁺² and NO₃⁻;
HgSO₄ is formed by the ions Hg⁺² and SO₄⁻²;
NaNO₃ is formed by the ions Na⁺ and NO₃⁻.
Thus, the spectator ions are Na⁺, SO₄⁻², Hg⁺², and NO₃⁻.