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3 years ago

CO + - 02 CO2 Balance the equation

Chemistry

1 answer:

poizon [28]3 years ago

5 0

Answer:

2co+o2=2co2

Explanation:

co+o2=co2

here is one carbon monoxide and two oxygen react with it and forms carbon dioxide..

2co+o2=2co2

hey mate hope it's help you.. please mark it as a brain.... answer

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Answer:

a high school classroom?

Explanation:

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2 years ago

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What is the observation of heating copper carbonate???.?

damaskus [11]

Answer:

1)This type of reaction is called thermal decomposition . Copper carbonate is green and copper oxide is black. You can see a colour change from green to black during the reaction. The carbon dioxide produced can be detected using limewater, which turns milky. 2) The extremely low pressure of the partial vacuum inside the can made it possible for the pressure of the air outside the can to crush it. A can is crushed when the pressure outside is greater than the pressure inside, and the pressure difference is greater than the can is able to withstand.

Explanation:

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3 years ago

A student walks 2 km in 30 minutes. What is the student’s average speed in km/h?

solmaris [256]

4 Km/Hr so.... 2/30=4/60

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3 years ago

One liter of a buffer contains 2.00 Molar NaA and 2.00 Molar HA. (A- is the anion of an acid) 15.00 g NaOH is added. (Assume no

madam [21]

Answer:

The new pH is 10.8031

Explanation:

Given information:

[NaA] = concentration = 2 M

[HA] = concentration = 2 M

V = volume = 1 L

15 g of NaOH added

Question: What is the new pH, pH = ?

Moles of NaA:

$n_{NaA} =2\frac{moles}{L} *1L=2moles$

Moles of HA:

$n_{HA} =2\frac{moles}{L} *1L=2moles$

Moles of NaOH:

$n_{NaOH} =15g*\frac{1mol}{40g} =0.375moles$

The reaction:

HA + NaOH → NaA + H₂O

Moles of NaA = 2 + 0.375 = 2.375 moles

Moles of HA = 2 - 0.375 = 1.625 moles

The value of Ka is 2.3x10⁻¹¹

The pKa:

$pKa=-logKa=-log(2.3x10^{-11} )=10.6383$

Applying the Henderson's Hasselbach equation

$pH=pKa+log\frac{molesNaA}{molesHA} =10.6383+log\frac{2.375}{1.625} =10.8031$

3 0

3 years ago

If I have 3.2 moles of gas at a pressure of 0.095 atm and at a temperature o 43 C what is the volume of the container that the g

andriy [413]

Answer

The volume of the container that the gas is in = 874.30 L

Explanation

Given:

Moles, n = 3.2 mol

Pressure, P = 0.095 atm

Temperature, T = 43 °C = (43 + 273.15 K) = 316.15 K

Molar gas constant, R = 0.0821 atm•L/mol•K

What to find:

The volume of the container that the gas occupied.

Step-by-step solution:

The volume of the container that the gas occupied can be calculated using the ideal gas equation.

$\begin{gathered} PV=nRT \\ \\ \Rightarrow V=\frac{nRT}{P}=\frac{3.2mol\times0.0821atm•L/mol•K\times316.15K}{0.095atm} \\ \\ V=\frac{83.058928\text{ }atm•L}{0.095\text{ }atm}=874.30\text{ }L \end{gathered}$

Therefore, the volume of the container that the gas occupied is 874.30 L

5 0

1 year ago