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serious [3.7K]
3 years ago
9

CO + - 02 CO2 Balance the equation

Chemistry
1 answer:
poizon [28]3 years ago
5 0

Answer:

2co+o2=2co2

Explanation:

co+o2=co2

here is one carbon monoxide and two oxygen react with it and forms carbon dioxide..

2co+o2=2co2

hey mate hope it's help you.. please mark it as a brain.... answer

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An animal skeleton has a carbon-14 decay rate of 13.1 disintegrations per minute per gram of carbon. When did the animal die? (A
Olenka [21]

Answer:

1034 yrs

Explanation:

The equation to use in this question is:

t = -2.303/k log (A/A₀) where

A=    present number of disintegrations

A₀ =  intial number of disintegrations

k =  decay constant

The decay constant we will obtain it from the given hal-life:

k: 0.693/t₁/₂,        t₁/₂ = half-life   ⇒

k: 0.693 / 5730 y =  1.209 x 10⁻⁴ /y⁻¹

t = - 2.303 / 1.209 x 10⁻⁴ /y⁻¹ x log (13.1/15.3) =  1034 yrs

3 0
3 years ago
A mixture containing nitrogen and hydrogen weighs 3.49 g and occupies a volume of 7.45 L at 305 K and 1.03 atm. Calculate the ma
-BARSIC- [3]

Answer:

Mass percent N₂ = 89%

Mass percent H₂ = 11%

Explanation:

First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:

  • 1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K
  • n = 0.307 mol

So now we know that

  • MolH₂ + MolN₂ = 0.307 mol

and

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g

So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:

Express MolH₂ in terms of MolN₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ = 0.307 - MolN₂

Replace that value in the second equation:

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
  • (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
  • 0.614 - 2MolN₂ + 28molN₂ = 3.49
  • 0.614 + 26MolN₂ = 3.49
  • MolN₂ = 0.111 mol

Now we calculate MolH₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ + 0.111 = 0.307
  • MolH₂ = 0.196 mol

Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:

  • N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂
  • H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂

Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%

Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%

5 0
3 years ago
The vapor pressure of liquid chloroform, CHCl3, is 100. mm Hg at 283 K. A 0.380 g sample of liquid CHCl3 is placed in a closed,
Katyanochek1 [597]

Answer:

a

No

b

100 mm Hg

Explanation:

From the question we are told that

The vapor pressure of CHCl3, is P = 100 \  mmHg =  \frac{100}{760}=  0.13156 \ atm

The temperature of CHCl3 is T  =  283 \  K

The volume of the container is V_c =  380mL =  380 *10^{-3}\  L

The temperature of the container is T_c  =  283 \  K

The mass of CHCl3 is m = 0.380 g

Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as

n  =  \frac{m }{M }

Here M is the molar mass of CHCl3 with the value M  =  119.38 \ g/mol

=> n  =  \frac{ 0.380 }{119.38 }

=> n  =  0.00318 \  mols

Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as

n_g  =  \frac{PV}{RT}

Here R is the gas constant with value R =  0.08206 L \  atm /mol\cdot  K

So

          n_g  =  \frac{0.13156* 380 *10^{-3} }{0.08206 * 283}

          n_g  =  0.00215 \  mols

Given that the number of moles of  CHCl3 evaporated is less than the number of moles of CHCl3  initially present , then it mean s that not all the liquid evaporated

At equilibrium the temperature of CHCl3 will be equal to the pressure of  air so the pressure at equilibrium is  100 mmHg

4 0
3 years ago
An atom that contains six protons six neutrons and six electrons has a mass of approximately
exis [7]
Six protons, six electrons, and six neutrons. The atom you are looking for is Carbon. The mass number is 12.

Mass number = protons + neutrons 
3 0
3 years ago
Following reactions<br>FeSO4+KOH<br>​
prohojiy [21]

Explanation:

FeSO _{4} + \: KOH \: →K _{2}SO _{4} \:  +  \: Fe(OH) _{2}

5 0
3 years ago
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