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Ivenika [448]
3 years ago
9

CH, (g) + 20 (g) → CO(g) + 2H 0(g)

Chemistry
1 answer:
galben [10]3 years ago
6 0
<h3>Answer:</h3>

126.14 g

<h3>Explanation:</h3>
  • Complete combustion of hydrocarbons yields water and carbon dioxide.
  • Methane is a hydrocarbon in the homologous series known as alkanes.
  • Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.

CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)

<u>We are given;</u>

  • 3.5 moles of Methane

We are required to determine the mass of H₂O produced

<h3>Step 1: Moles of H₂O produced</h3>
  • From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.

Therefore, Moles of methane = Moles of H₂O × 2

Hence, Moles of H₂O = 7.0 moles

<h3>Step 2: Mass of H₂O produced </h3>

We know that; mass = Moles × Molar mass

Molar mass of water = 18.02 g/mol

Therefore;

Mass of water = 7.0 moles × 18.02 g/mol

                       = 126.14 g

Thus, the mass of water produced is 126.14 g

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( HELP) The following system is at equilibrium. In which direction (right or left) will the equilibrium position shift with the
Alex Ar [27]

a) right

b) left

c) left

d) right

e) right

f) no effect

d) left

Explanation:

We have the following chemical reaction:

3 NO (g) ⇔ N₂O (g) + NO₂ (g) + 154.9 kJ

a) right, because by lowering the temperature you remove the heat generated by the reaction, and the reaction is able to generate more heat with the reaction proceeding from left to right.

b) left, because by increasing the temperature you add heat to the reaction and by doing so the reaction from right to left will be promoted.

c) left, increasing the concentration of N₂O the equilibrium will shift to left in order to consume the N₂O added.

d) right, increasing the concentration of NO the equilibrium will shift to right in order to consume the NO added.

e) right, decreasing the concentration of N₂O the equilibrium will shift to right in order to produce the removed N₂O.

f) no effect, adding a catalyst will not shift the equilibrium position, it will only modify the time in which the equilibrium is achieved and the energy required to achieve the equilibrium state.

g) left, by increasing the volume the equilibrium will shift to the part where more moles are produced (there are 3 moles on left side while in the right side there are 2 moles).

Learn more about:

Le Chatelier Principle

brainly.com/question/4356622

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#learnwithBrainly

8 0
3 years ago
A solution is prepared by dissolving 0.5636 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq
zepelin [54]

Answer:

The final molarity of the diluted oxalic acid solution is 0.002504 M

Explanation:

Step 1: Data given

Mass of oxalic acid (H2C2O4) = 0.5636 grams

Volume of the solution = 100.0 mL = 0.100 L

A 10 ml of this solution diluted in 250 ml of solution.

Molecular weight of H2C2O4  = 90.03 g/mol

Step 2: Calculate  initial moles of H2C2O4

Moles H2C2O4  = mass / molar mass

Moles H2C2O4  = 0.5636 grams / 90.03 g/mol

Moles H2C2O4 = 0.00626 moles

Step 3: Calculate molarity of the solution

Molarity = moles / volume

Molarity = 0.00626 moles / 0.100 L

Molarity = 0.0626 M

Step 4: Calculate moles of a 10.00 mL aliquot

Moles = 0.0626 M * 0.010 L

Moles = 0.000626 moles

Step 5: Calculate the new molarity

Molarity = 0.000626 moles / 0.250 L

Molarity = 0.002504 M

The final molarity of the diluted oxalic acid solution is 0.002504 M

6 0
3 years ago
Since water can be prepared in the laboratory
Arturiano [62]

Answer:

# In a familiar high-school chemistry demonstration, an instructor first uses electricity to split water into its constituent gases, Hydrogen and Oxygen. Then, by combining the two gases and igniting them with a spark, the instructor changes the gases back into water with a loud pop (That means the energy is released in the process).

# There are new other ways to produce water in laboratory, however, the scientists can not produce water in large quantity for the masses, because of some reasons.

1- Theoretically, this is possible, but it would be an extremely dangerous process. Since Hydrogen is extremely flammable and Oxygen supports combustion, it wouldn’t take much to create this force, but we also have an explosion. That’s why this process can be a deadly one if our experiment is big enough.

2- Personally, I think that it makes no sense to produce water in a laboratory ( or in a large plant) for people to use as daily water. The much more important thing we need to do is to save our environment, our planet Earth. Because the daily water people drink contains not just water molecules but other minerals, the marine life is depend not just in water molecules but diferent factors, etc.

Explanation:

This is just my personal opinion. Hope that can help you a little. Have a nice day

7 0
3 years ago
How much greater is the pressure at the deepest part of the ocean compared to that found at sea level?
Leno4ka [110]
The deepest part of the ocean is the Marianas Trench, where the water pressure is 1,000 times that of which is found at sea level.
6 0
3 years ago
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professor190 [17]

Answer:

a

Explanation:

the solution is extremely acidic and will dissolve the zinc rod

3 0
3 years ago
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