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3 years ago

CH, (g) + 20 (g) → CO(g) + 2H 0(g)

Chemistry

1 answer:

galben [10]3 years ago

6 0

<h3>Answer:</h3>

126.14 g

<h3>Explanation:</h3>

Complete combustion of hydrocarbons yields water and carbon dioxide.
Methane is a hydrocarbon in the homologous series known as alkanes.
Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.

CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)

<u>We are given;</u>

3.5 moles of Methane

We are required to determine the mass of H₂O produced

<h3>Step 1: Moles of H₂O produced</h3>

From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.

Therefore, Moles of methane = Moles of H₂O × 2

Hence, Moles of H₂O = 7.0 moles

<h3>Step 2: Mass of H₂O produced </h3>

We know that; mass = Moles × Molar mass

Molar mass of water = 18.02 g/mol

Therefore;

Mass of water = 7.0 moles × 18.02 g/mol

= 126.14 g

Thus, the mass of water produced is 126.14 g

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Which of the following statement(s) about chemical bonding

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Answer:

The correct answer is - option C.

Explanation:

Given: the melting point of HCl is

-114.8 °C, which suggests that below this temperature HCl will be solid.

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Solid -114.8 - Ordered arrangement

Liquid -85.1c - Less orderly arranged

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3 years ago

How many atoms of carbon are represented in 3CH3CH20

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6 carbon atoms

          H H
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3 x   H - C - C - O - H
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3 years ago

If an object that stands 3 centimeters high is placed 12 centimeters in front of a plane mirror, how far from the mirror is the

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Answer:

the mirror is 12 cm away from the image

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3 years ago

The thermite reaction reacts iron (III) oxide, Fe2O3, with aluminium powder,Al, the form aluminium oxide, Al2O3 and iron, Fe.

lara [203]

Answer:

<u><em>This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.</em></u>

Explanation:

To start, the thermite equation must be balanced.

I find:

1Fe2O3 + 2Al = 1Al2O3 + 2Fe

This tells us we need 2 moles of Al for every 1 mole of Fe2O3.

Now calculate the moles of each reactant:

Moles Fe2O3: 16.0 g/159.7 g/mole = <u>0.100 moles Fe2O3</u>

Moles Al: 8.1 /26.98 g/mole = <u>0.300 moles Al</u>

The balanced equation says that in order to react all of the Fe2O3 we'd need twice that amount (in moles) of the Al. (0.100 moles Fe2O3)*(2) = 0.200 moles Al.

<u>Which of the two reactants is the limiting reagent?</u>

We have more than enough moles of Al to react with 0.10 moles of Fe2O3. (We have 0.300 moles Al and all we need is 0.200 moles to react with the 0.10 moles of Fe2O3. <em>Fe2O3 is the limiting reagent.</em>

<u><em>Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.</em></u>

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed. Since Fe2O3 is the limiting reagent, we will assume that it completely reacts. That means 0.1 moles of Fe2O3 is reacted. Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe. At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

5 0

2 years ago