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Ivenika [448]
3 years ago
9

CH, (g) + 20 (g) → CO(g) + 2H 0(g)

Chemistry
1 answer:
galben [10]3 years ago
6 0
<h3>Answer:</h3>

126.14 g

<h3>Explanation:</h3>
  • Complete combustion of hydrocarbons yields water and carbon dioxide.
  • Methane is a hydrocarbon in the homologous series known as alkanes.
  • Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.

CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)

<u>We are given;</u>

  • 3.5 moles of Methane

We are required to determine the mass of H₂O produced

<h3>Step 1: Moles of H₂O produced</h3>
  • From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.

Therefore, Moles of methane = Moles of H₂O × 2

Hence, Moles of H₂O = 7.0 moles

<h3>Step 2: Mass of H₂O produced </h3>

We know that; mass = Moles × Molar mass

Molar mass of water = 18.02 g/mol

Therefore;

Mass of water = 7.0 moles × 18.02 g/mol

                       = 126.14 g

Thus, the mass of water produced is 126.14 g

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