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3 years ago

The angle measures of a triangle are shown in the diagram.

Mathematics

1 answer:

STALIN [3.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

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For the right triangle find the missing length. Round your answer to the nearest tenth.

monitta

Answer:

Step-by-step explanation:

w = 4 units

7 0

3 years ago

What are the solutions for the equation 2cos0+1=0 ?

Oksanka [162]

Answer:

2cos0=-1

cos0=-1/2

proved

4 0

4 years ago

Find the value of x for which m//n A. 10 B. 12 C. 40 D. 52.

fenix001 [56]

m//n if the external alternating angles are equal, that means:
(3x+12)°=48°

Solving for x:
3x+12=48
3x+12-12=48-12
3x=36
3x/3=36/3
x=12

Answer: Option B. 12

6 0

3 years ago

Read 2 more answers

Solve. Express your answer as a simplified fraction 7/8 divided by 9/8. Help

nasty-shy [4]

Answer:

7/9

Step-by-step explanation:

Plz give me brainleist worked hard thank u very much in advance.

8 0

3 years ago

Estimate the time it takes for a free fall drop from 10 meters height. Also estimate the time a 10 m platform diver would be in

murzikaleks [220]

Answer:

a) $t = \sqrt{\frac{2 *10m}{9.8 m/s^2}}=1.43s$

b) $4.9t^2 -2t -10 =0$

And we can use the quadratic formula to solve it:

$t = \frac{2 \pm \sqrt{(-2)^2 -4(4.9)(-10)}}{2*4.9}$

$t =\frac{2 \pm \sqrt{200}}{9.8}$

$t_1 =1.65 s, t_2 =-1.24 s$

And since the time can't be negative the correct option would be $t=1.65 s$

Step-by-step explanation:

For this case we can use the following kinematics formulas:

$y_f = y_o + V_o t + \frac{1}{2} a t^2$

For this case we assume that the only acceleration is the gravity a = g =9.8 m/s^2. And for this case we can assume that the reference point is $y_o =0$ and the final height would be $y_f = -10 m$ since is below the initial point.

Teh acceleration would be a=-g, since the gravity is acting dowward, we assume that the initial velocity is 0, so then we have everything to replace and we got:

$-10 m = 0m + (0m/s)t -\frac{1}{2} (9.8 m/s^2) t^2$