N. Sucrose decomposes in acid solution into glucose and fructose according to a first-order rate law,
1 answer:
<u>Answer: </u>
The fraction of a sample of sucrose remains after 9.00 h is 0.155.
<u>Explanation:
</u>
According to the fundamentals for a first order reaction,
k=
it is given that 0.5 t = 3.33 hours;
k = = = 0.208
then 0.208 =
=
= 0.812
taking antilog on both sides we get
= antilog(0.812) = = 6.486
= = 0.155
Hence the fraction of sample of sucrose that remains after 9 hours is 0.155.
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