Answer:
The most stable conformer would be the anti-conformer when the substituent methyl groups are farthest away from each other.
Explanation:
Isomers are chemical compounds with the same molecular formula but with different molecular structures.
Conformers are a special type of isomers that produce different structures when the substituents of a Carbon-Carbon single bond (C-C) are rotated.
In 2,3 dimethyl butane, the substituent methyl groups are located around the second and third Carbon to Carbon single bond.
To achieve a stable configuration, the methyl group substituents need to be as far apart as possible (that is, in an anti-position) to minimise repulsion.
The closer the methyl groups are to each other, the more they repel each other and the more unstable the conformer becomes.
Answer:
Explanation:
density = m/v
answer = 2.0819 g/ml
rounded (correct sig figs) = 2.08
Answer:
0.78 M
Explanation:
First, we need to know which is the value of Kc of this reaction. In order to know this, we should take the innitial values of N2, O2 and NO and write the equilibrium constant expression according to the reaction. Doing this we have the following:
N2(g) + O2(g) <------> 2NO(g) Kc = ?
Writting Kc:
Kc = [NO]² / [N2] * [O2]
Replacing the given values we have then:
Kc = (0.6)² / (0.2)*(0.2)
Kc = 9
Now that we have the Kc, let's see what happens next.
We add more NO, until it's concentration is 0.9 M, this means that we are actually altering the reaction to get more reactants than product, which means that the equilibrium is being affected. If this is true, in the reaction when is re established the equilibrium, we'll see a loss in the concentration of NO and a gaining in concentrations of the reactants. This can be easily watched by doing an ICE chart:
N2(g) + O2(g) <------> 2NO(g)
I: 0.2 0.2 0.9
C: +x +x -2x
E: 0.2+x 0.2+x 0.9-2x
Replacing in the Kc expression we have:
Kc = [NO]² / [N2] * [O2]
9 = (0.9-2x)² / (0.2+x)*(0.2+x) ----> (this can be expressed as 0.2+x)²
Here, we solve for x:
9 = (0.9-2x)² / (0.2+x)²
√9 = (0.9-2x) / (0.2+x)
3(0.2+x) = 0.9-2x
0.6 + 3x = 0.9 - 2x
3x + 2x = 0.9 - 0.6
5x = 0.3
x = 0.06 M
This means that the final concentration of NO will be:
[NO] = 0.9 - (2*0.06)
[NO] = 0.78 M
Sucrose is an example of a non- reducing sugar.
Your welcome :)
Answer:
1272 pound
Explanation:
From the question given above, the following data were obtained:
Pressure (P) = 38 psi
Area (A) = 12 cm by 18 cm
Force (F) =?
Next, we shall determine the area. This can be obtained as follow:
Area (A) = 12 cm by 18 cm
A = 216 cm²
Next, we shall convert 216 cm² to square inch (in²). This can be obtained as follow:
1 cm² = 0.155 in²
Therefore,
216 cm² = 216 cm² × 0.155 in² / 1 cm
216 cm² = 33.48 in²
Finally, we shall determine the force exerted. This can be obtained as follow:
Pressure (P) = 38 psi = 38 lbf/in²
Area (A) = 33.48 in²
Force (F) =?
P = F/A
38 = F / 33.48
Cross multiply
F = 38 × 33.48
F = 1272 pound
Thus, the force exerted is 1272 pound
