False. They don't borrow electrons at all. They already have their respective electron affinities. This is called as electronegativity, and it's an occurence where it already has its own from its actual structure. It never borrows any electrons at all.
This problem is asking for the for pH when a solution of potassium hydroxide is diluted to the double of its initial volume. Thus, the answer turns out to be 11.0.
<h3>pH calculations</h3>
In chemistry, pH calculations are performed based on the following equation relating the pH and the concentration of hydrogen ions in the solution:
However, since this problem involves a strong base, KOH as potassium hydroxide, one must calculate the pOH instead, and then convert it to pH with the following equations:
In addition, due to the fact it is diluted from 10. mL to 20. mL (with the 10. mL of added distilled water), one needs to use the dilution equation in order to calculate the correct concentration of KOH:
Hence, the pOH turns out to be:
And thereby the pH:
Learn more about pH calculations: brainly.com/question/1195974
Answer : The concentration of and at equilibrium is, 0.0031 M and 0.0741 M respectively.
Explanation : Given,
Moles of = 0.166 mol
Volume of solution = 2.15 L
First we have to calculate the concentration of
Now we have to calculate the concentration of and at equilibrium.
Initial conc. 0.0772 0 0
At eqm. 0.0772-x x x
The expression for equilibrium constant is:
By solving the term, we get the value of 'x'.
x = 0.0741
Thus,
The concentration of at equilibrium = (0.0772-x) = (0.0772-0.0741) = 0.0031 M
The concentration of at equilibrium = x = 0.0741 M
Answer:
Sodium
because it burns with a yellow-orange flame.
Explanation:
It relates with Barium which burns with yellowish green flame