Answer:
The student should weigh out 61.2g of ethanolamine [6.12 * 10]
Explanation:
In this question, we are expected to calculate the mass of ethanolamine needed to make 60.0ml of it given that the density of the ethanolamine in question is 1.02g/cm^3
Mathematically, it has been shown that mass = density * volume
Hence, by multiplying the density by the volume, we get the mass.
Now, from the question we can see that we have the values for the density and the volume. We now need to get the mass.
Since cm^3 is same as ml, we need not perform any conversion.
Hence, the needed mass is:
60 * 1.02 = 61.2g
A...because both of them(carbon and oxygen)are nonmetal
Answer:
160
Explanation:
p*v/t = constant
or
p1*v1/t1 = p2*v2/t2
pressure is not stated in question so we get rid of it on both sides
v1/t1 = v2/t2
we are finding temperature so we flip the entire equation
t1/v1 = t2/v2
200/5 = t2/4
4(200/5) = t2
=160
Answer:
240 g/mol
Explanation:
We'll begin by writing the chemical formula of Disodium sulfide nonahydrate. This is illustrated below:
The molecular formula of disodium sulfide nonahydrate is Na₂S.9H₂O
Finally, we shall determine the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O. This can be obtained by adding the individual molar mass of the element present in the compound as illustrated below:
Molar mass of Na₂S.9H₂O = (23×2) + 32 + 9[(2×1) + 16]
= 46 + 32 + 9[2 + 16]
= 46 + 32 + 9[18]
= 46 + 32 + 162
= 240 g/mol
Thus, the molar mass of disodium sulfide nonahydrate, Na₂S.9H₂O is 240 g/mol
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