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Juli2301 [7.4K]
3 years ago
13

What is the concentration of hydrogen ions in a solution of ph = 4.0 ASAP PLEASE

Chemistry
1 answer:
adell [148]3 years ago
4 0

<u>Answer:</u>

concentration of H  ions = 0.0001 M

<u>Explanation:</u>

Base 10 logarithm of the H+ concentration when multiplied by -1 is equal to the pH value of a solution. By reversing this formula, we can find the concentration of the H+ in the solution:

pH = -㏒ (concentration of H+)

or 10^{-pH} = = concentration of H+

We know that, pH of the solution is 4.0,

so 10^{-4} = 0.0001

Therefore, the concentration of Hydrogen ions in a solution of pH = 4 is 0.0001 M.


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What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

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