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Juli2301 [7.4K]
2 years ago
13

What is the concentration of hydrogen ions in a solution of ph = 4.0 ASAP PLEASE

Chemistry
1 answer:
adell [148]2 years ago
4 0

<u>Answer:</u>

concentration of H  ions = 0.0001 M

<u>Explanation:</u>

Base 10 logarithm of the H+ concentration when multiplied by -1 is equal to the pH value of a solution. By reversing this formula, we can find the concentration of the H+ in the solution:

pH = -㏒ (concentration of H+)

or 10^{-pH} = = concentration of H+

We know that, pH of the solution is 4.0,

so 10^{-4} = 0.0001

Therefore, the concentration of Hydrogen ions in a solution of pH = 4 is 0.0001 M.


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Explanation:

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2 years ago
8moles of Na2Cr2O2 is how much mass​
Margaret [11]

\boxed{\boxed{\mathfrak{ 1\: mole \:of \:Na_2Cr_2O_2\: = \:it's \:Gram\: Mol. \: mass}} }

\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}

= 2 × 23 + 2 × 52 + 2 × 16

= 182 grams

1 mole of Na_2Cr_2O_2 weighs = 182 g

8 moles weigh = 8× 182

=\mathfrak{\blue {\boxed{\underline {1456 \: grams}}}}

or

\mathfrak{\blue {\boxed{\underline {1. 46 \:kg }}}}

5 0
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Which statement best describes alpha decay?(1 point)
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Problem PageQuestion Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume
IgorC [24]

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.

Be sure your answer has the correct number of significant digits.

Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm  (at STP)

V = Volume of gas = 3.16 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K=

n=\frac{PV}{RT}

n=\frac{1atm\times 3.16L}{0.0820 L atm/K mol\times 273K}=0.141moles

CH_4+4Cl_2\rightarrow 4HCl+CCl_4

According to stoichiometry:

4 moles of chlorine produces = 1 mole of carbon tetrachloride

Thus 0.141 moles of methane produces = \frac{1}{4}\times 0.141=0.0352 moles of carbon tetrachloride

volume of carbon tetrachloride =moles\times {\text {Molar volume}}=0.0352mol\times 22.4L/mol=0.788L

Thus volume of carbon tetrachloride that would be produced is 0.788 L

8 0
3 years ago
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