Answer:
Equation of midsegment line: y = (-1/4)x + 2.
Step-by-step explanation:
If the parallel sides of a trapezoid are contained by the lines:-
y = (-1/4)x +5 and y = (-1/4)x - 1
Midsegment of any trapezoid is the line segment
1. that is parallel to pair of parallel side of trapezoid and
2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.
It means the midsegment would have same slope as the parallel lines and y-intercept would be in the middle of intercepts of parallel lines.
So y = mx + b
where m = -1/4 and b = (5 - 1)/2 = 4/2 = 2.
Hence, the equation of midsegment would be y = (-1/4)x + 2.
Answer:
3. undefined (vertical line)
4. 1
7. -4
8. 3
11. undefined (vertical line)
12. -1/3
Step-by-step explanation:
You can use the slope formula to calculate the slope which is (y2-y1)/(x2-x1)
3. (-4 - (-2)) / (6-6) denominator is 0 here so the slope is undefined (vertical line)
4. (7 - 1) / (-2 - (-4)) = 6 / 6 = 1
7. (1 - (-7)) / (2 - 4) = 8 / -2 = -4
8. (-1 - 5) / (0 -2 ) = -6 / -2 = 3
11. (3 - 0) / (-6 - (-6)) = 3 / 0 = undefined (vertical line
12. (2 - 3) / (-5 - (-2) = 1 / -3 = -1/3
So it is distance from zero so 6+15=21
1 2 3 4 5 6 7 8 9 10 (11) 12 13 14 15 16 17 18 19 20 21
eliminate one from each side till you find the middle
Answer:
25%
Step-by-step explanation:
So first we need to find out how many hours the school has class. Its 4 hours from 8 to noon, then another 2 from noon to 2. This means the school has class 6 hours a day.
Now we need to figure out the percent. we need to have hours of school over total hours or 6/24
6/24
we can simplify this by dividing both sides by 6
(6/6)/(24/6)=1/4
1/4 is 25%
The school holds class for 25% of the day
