Answer:
The correct option is;
DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)
Step-by-step explanation:
Given that we have;
1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC
2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC
3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC
Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;
AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))
∴ (sin(m∠ADE)) = (sin(m∠ABC))
m∠ADE) = m∠ABC).
Answer: a) 0.2222, b) 0.3292, c) 0.1111
Step-by-step explanation:
Since we have given that
Let the probability of getting head be p.
Since, its head is twice as likely to occur as its tail.
a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?
So, here, n = 3
Now,
b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?
2 tails means 3 heads.
So, it becomes,
c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?
Hence, a) 0.2222, b) 0.3292, c) 0.1111
Answer: t = 10
Step-by-step explanation:m
Given that; n₁ = 10, n₂ = 10
ж₁ = 50, ж₂ = 30
Sˣ₁ = 20, Sˣ₂ = 20
Now using TEST STATISTICS
t = (ж₁ - ж₂) / √ ( Sˣ₁/n₁ + Sˣ₂/n₂ )
so we substitute our figures
t = ( 50 - 30 ) / √ ( 20/10 + 20/10 )
t = 20 / √4
t = 10
Answer:
I believe the answer is D.
Step-by-step explanation:
to do this you would need to shade in 7 out of the 10 rows going horizontally or vertically it doesnt really matter as long as u shade in 7 rows of them
