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Marat540 [252]
3 years ago
7

What are the zeros of the polynomial function: f(x) = x3 + x2 – 6x ? ...?

Mathematics
2 answers:
Vikki [24]3 years ago
7 0
The solution to the problem is as follows:

  
<span>x³ + x² − 6x = 0 </span>
<span>x (x² + x − 6) = 0 </span>
<span>x (x − 2) (x + 3) = 0 </span>
<span>x = 0, 2, −3 </span>


<span>f(x) = 2x³ + 5x² + 6x − 4 </span>
<span>f(−x) = −2x³ + 5x² − 6x − 4 </span>

<span>Let's look at signs only and how many sign changes there are: </span>
<span>f(x) = + + + − </span>
<span>1 sign change ----> 1 positive root </span>
<span>f(−x) = − + − − </span>
<span>2 sign changes ----> 2 or 0 negative roots </span>

<span>Min. number of real roots = 1 ----> max. number of complex roots = 2 </span>
<span>Max. number of real roots = 3 ----> min. number of complex roots = 0
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
IrinaK [193]3 years ago
3 0

Answer:

it B.x=-2,x=0and x=3

Step-by-step explanation:

apexs

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