It would be in the first quadrant since the second quadrant is on the other side of the y-axis.
 
        
             
        
        
        
All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.
2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30
3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents
4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
        
             
        
        
        
Answer:
   -2 > -6  . . .   or  . . .  R > S
Step-by-step explanation:
If you plot the temperatures of the two cities on a number line, you see that the temperature for City R is plotted to the right of the temperature for City S. This means the temperature of City S is less than that of City R.
If your inequality relates cities:
   S < R   or   R > S
If your inequality relates temperatures:
   -6 < -2   or   -2 > -6
 
        
             
        
        
        
Answer:
Option A
Step-by-step explanation:
The response variable is the dependent variable whose variation depends on other variables and in this case it is the type of surgery either total knee replacement or partial knee replacement.
While the explanatory variable which is the independent variable manipulated by the researcher for the given experimental study is the amount of activity the patients were able to do after their respective surgeries.
 
        
             
        
        
        
Answer:
 <em>As </em><em>we </em><em>know </em><em>that </em><em>there </em><em>is </em><em>a </em><em>radius </em><em>which </em><em>is </em><em>2 </em><em>cm</em>
<em>so </em>
<em>circumference </em><em>=</em><em> </em><em>2</em><em> </em><em>π</em><em> </em><em>r</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>*</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>*</em><em> </em><em>2</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>.</em><em>5</em><em>7</em><em>c</em><em>m</em>
<em>it's </em><em>circumference </em><em>is </em><em>1</em><em>2</em><em>.</em><em>5</em><em>7</em><em> </em><em>cm</em>