Answer:
Distance around the pool = 162.8 feet
Area of the pool = 957 square feet
Step-by-step explanation:
Distance around the swimming pool = Perimeter of the pool
Perimeter of the pool which is a composite figure will be,
= Circumference of the semicircle + Sum of three sides of the pool
= πr + 2×(length of the pool) + width of the pool
= 3.14×(10) + 2×40 + 20
= 62.8 + 80 + 20
= 162.8 ft
Area of the pool = Area of the semicircle + Area of the rectangular pool
= 
= 
= 157 + 800
= 957 square feet
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
Answer:
<h2>A. 1</h2>
Step-by-step explanation:
Use:
|a| = a for a ≥ 0 or |a| = -a for a < 0
PEMDAS:
P Parentheses first
E Exponents
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
========================================
|8 - 7| · 4 + 3(-1)
= |1| · 4 - 3
= 1 · 4 - 3
= 4 - 3
= 1
Answer:
Solution given:
x^3 - 2x^2 -x+2
take common from two each term
x²(x-2)-1(x-2)
take common again and keep left one on other bracket
<u>(x-2)(x²-1) or (x-1)(x+1)(x-2)</u> is a required answer.
note:using formula a²-b²=(a+b)(a-b) for x²-1.
