Answer:
the first one, v < 1 23/25
Step-by-step explanation:
multiply both sides by 6 and divide by 5
v < 48/25, or v < 1 23/25
9514 1404 393
Answer:
n(m(3)) = 7
Step-by-step explanation:
n(m(3)) = n(2·3 -5) = n(1) = 2·1 +5
n(m(3)) = 7
Get like terms together. you might have to move across the equals sign
3x-x=-6+82
2x=76
x=38
1) No; you are incorrect. "0" is NOT a solution.
Plug in "0" for "x" ;
8*0² + 23 =? 823? ;
8*0 + 23 =? 823? ;
0 + 23 = ? 823 ? ; No! ; "0 + 23 = 23 " ; NOT "823" .
_________________________________________________
2) The answers: x = 10, -10 ; or, write as: x = ± 10 .
_________________________________________________
To solve:
GIven: 8x² + 23 = 823 ;
Subtract "23" from EACH SIDE of the equation:
_____________________________________________
8x² + 23 - 23 = 823 - 23 ;
to get:
8x² = 800 ;
Now, divide EACH SIDE of the equation by "8" ;
8x² / 8 = 800 / 8 ;
to get: x² = 100 ;
Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
√(x²) = √(100) ;
x = <span>± 10 .
The answers: x = 10, -10 ; or, write as: x = </span><span>± 10 .
_____________________________________________________</span>
Answer:
Not possible.
Step-by-step explanation:
Addition of Matrix A and Matrix B is possible only if the order of matrix A is same as the order of matrix B.
Order of a matrix with 
rows and 
columns is 
.
Here, matrix A is ![\left[\begin{array}{ccc}2&-4\\-4&10\\0&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%5C%5C-4%2610%5C%5C0%26-8%5Cend%7Barray%7D%5Cright%5D)
Matrix B is ![\left[\begin{array}{ccc}0&-4&6\\2&-10&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-4%266%5C%5C2%26-10%264%5Cend%7Barray%7D%5Cright%5D)
.
Multiplying a matrix by a constant doesn't change its order.
So, order of matrix A is 
as it has 3 rows and 2 columns.
The order of matrix 3B is 
as it has 2 rows and 3 columns.
Therefore, addition is not possible as the order is different.
