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kari74 [83]
4 years ago
9

A friend runs up to you and excitedly explains that she has found that she has found a function g with the following properties:

Mathematics
1 answer:
Vika [28.1K]4 years ago
7 0
Given the start point of (0,1) and (1,5), the average slope is (5-1)/(1-0) = 4.  So the finding that g'(x) for the interval is <=3 cannot be true.  It might be for a small segment but not the entire interval.
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A machine at a graphic design studio produces paper labels for juice bottles. This graph represents the number of labels produce
Jobisdone [24]

Answer:

Option B, would be the correct answer: 75 labels per minute

Step-by-step explanation:

The number of labels produced per minute would be a constant value which would be the slope of this graph represented above.

Slope = \frac{rise}{run}

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HELP please urgent!! - PLEASE CLICK, NEED HELP -
Makovka662 [10]

Answer:

y=3x^2-12x-135

Step-by-step explanation:

The standard form of a quadratic is  y=ax^2+bx+c

We will use the x and y values from each of our 3 points to find a, b, and c.  Filling in the x and y values from each point:

First point (-5, 0):

0=a(-5)^2+b(-5)+c and

0 = 25a - 5b + c

Second point (9, 0):

0=a(9)^2+b(9)+c and

0 = 81a + 9b + c

Third point (8, -39):

-39=a(8)^2+b(8)+c and

-39 = 64a + 8b + c

Use the elimination method of solving systems on the first 2 equations to eliminate the c.  Multiply the first equation by -1 to get:

-25a + 5b - c = 0

81a + 9b + c = 0

When the c's cancel out you're left with

56a + 14b = 0

Now use the second and third equations and elimination to get rid of the c's.  Multiply the second equation by -1 to get:

-81a - 9b - c = 0

64a + 8b + c = -39

When the c's cancel out you're left with

-17a - 1b = -39

Between those 2 bolded equations, eliminate the b's.  Do this by multiplying the second of the 2 by 14 to get:

56a + 14b = 0

-238a - 14b = -546

When the b's cancel out you're left with

-182a = -546 and

a = 3

Use this value of a to back substitute to find b:

56a + 14b = 0 so 56(3) + 14b = 0 gives you

168 + 14b = 0 and 14b = -168 so

b = -12

Now back sub in a and b to find c:

0 = 25a - 5b + c gives you

0 = 75+ 60 + c so

0 = 135 + c and

c = -135

Put that all together into the standard form equation to get

y=3x^2-12x-135

6 0
4 years ago
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