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3 years ago

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Write an expression that shows how to multiply 4 times 362 using place value and expanded form

1 answer:

luda_lava [24]3 years ago

3 0

$362=300+60+2\\\\4\times362=4\times(300+60+2)\\\\ues\ distributive\ property:\\\\4\times300+4\times60+4\times2=1200+240+8=\boxed{1448}$

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Please help me answer this question

sergejj [24]

Answer:

72km

Step-by-step explanation:

alex : tomos : annabelle = 2 : 3 : 4

if tomos drove 24km

tomos ratio is 3

so 3 --> 24

<em>1 --> 8 </em>

<u>total ratios --> 2 + 3 + 4 = 9</u>

so total journey is 9 --> 9 * 8 = 72km

6 0

2 years ago

Use inverse operations to solve equation 15=x/6-1

beks73 [17]

Answer:

x=90.

Step by step explanation:

To solve the expression $15=\frac{x}{6}-1$ , and obtaining a value for x we can do the following:

Add 1 both sides of the equation. This will result in $15+1=\frac{x}{6}-1+1$ ⇒ $16=\frac{x}{6}$ .
Multiply both sides by 6, which yields $15\times6=\frac{x}{6}\times6$ . This results in $90=x$ .

7 0

4 years ago

Given:3x + y = 1. Solve for y.

tatyana61 [14]

Answer:

Step-by-step explanation:

y= -3x+1

you use inverse operations, and since you want the y alone, you subtract 3x on both sides, giving you y= -3x+1

7 0

4 years ago

Read 2 more answers

Order them from least to great

laiz [17]

Answer:

-21/2 <-5/2 < - 2 < - 1.75 <-1 <1.75 <9/4

4 0

3 years ago

Will crown the correct answers brainliest 3x

Solnce55 [7]

Answer :

(1) $\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) $\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}$

(3) $\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}$

(4) $\frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}$

(5) $\frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}$

(6) $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}$

Step-by-step explanation :

(1) The given expression is: $\frac{1}{x}+\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) The given expression is: $\frac{1}{5x}+\frac{1}{3y}$

$\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}$

(3) The given expression is: $\frac{1}{7x}-\frac{1}{2y}$

$\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}$

(4) The given expression is: $\frac{2}{5x}+\frac{3}{7y}$

$\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}$

(5) The given expression is: $\frac{7}{11x}-\frac{1}{33y}$

$\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}$

(6) The given expression is: $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}$

$\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}$

7 0

3 years ago