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3 years ago

7

A bag contains white marables and red marables,126 in total.the number of white marables is 6 more than 5 times the number of re

d marables.how many marables are there

1 answer:

Tanya [424]3 years ago

6 0

Answer:

126

Step-by-step explanation:

you typed a bag contains white marables and red marables, <u><em>126 in total</em></u>.

please tell me if i read it wrong.

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6 9/10 x 20/21<br> Simplify your answer completely and change to a mixed number.

Sidana [21]

Answer:

$6\frac{4}{7}$

Step-by-step explanation:

Hello,

I am going to start with to change to a improper fraction:

1. I will convert 6 and 9/10 into a improper fraction:

$69/10$

2. Now that I have converted the mixed fraction into a improper I can multiply the numerator and the denominator.

$69 * 20 / 21 * 10 = 1380/210$

3. Now I can simplify this value and convert it into a mixed fraction

$46/7$

After further simplifying I can convert this into an mixed number

$6\frac{4}{7}$

5 0

3 years ago

VERY IMPORTANT I NEED HELP!!!

Advocard [28]

Answer:

2√3

Step by step Explanation:

$= > \frac{ \sqrt{96} }{ \sqrt{8} } \\ \\ = > \frac{ \sqrt{12 \times 8} }{ \sqrt{8} } \\ \\ = > \frac{ \sqrt{12} \times \sqrt{8} }{ \sqrt{8} } \\ \\ = > \sqrt{12} \\ \\ = > \sqrt{4 \times 3} \\ \\ = > \sqrt{2 \times 2 \times 3} \\ \\ = > 2 \sqrt{3}$

3 0

3 years ago

Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe

bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W = 100 m

The largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W) - L = 2W + L

Now, fencing is given as 500 m

⇒ 2W + L = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L = 2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W = 100 m

The maximized area = Length x Width

= 200 m x 100 m = 20, 000 sq m

Hence, the largest area that can be enclosed is 20,000 sq m.

6 0

3 years ago

(x - 3) (3x + 7) = 0 Find the values of x.

expeople1 [14]

(x-3)(3x+7)=0
x-3=0 or 3x+7=0

1. x-3=0
x₁=3

2. 3x+7=0
3x=-7
x₂=-7/3 = -2(1/3)

8 0

3 years ago

Read 2 more answers

The residents of a downtown neighborhood designed a triangular-shaped park as part of a city beautification program. The park i

ycow [4]

You have x , x+7, and 7x-7. When you add those up and equal it to 180 you can get your x. X equals 20
So one angle is 20 degrees
The second angle is 27 degrees
And the third angle is 133 degrees.

8 0

3 years ago