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Zarrin [17]
3 years ago
9

Answer!!!!! Help!!!

Mathematics
1 answer:
guajiro [1.7K]3 years ago
7 0

Answer:

The answer is postulate

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I need help with number 17. <br><br> Please explain your answer.
Phoenix [80]
2*.75= 1.5

2(x+1.1)= 2x+2.2

2x+2.2+1.5

2x+3.7

the answer to the question is e
6 0
3 years ago
How can you subtract fractions with unlike denominators?
Rama09 [41]

Answer:

No, You can't. You have to make their denominators equal!

-\frac{7}{10}

Step-by-step explanation:

So first, you make their denominators equal!

\frac{1*2}{5*2} =\frac{2}{10}=\frac{1}{5}

Multiplying both the numerator and denominator with the same number results in the same fraction, just un-simplified

So, we input it!

\frac{2}{10} -\frac{9}{10} = -\frac{7}{10}

There you go!

Hope you get better at math!(gets wayyyyyyyyyyy...y more complicated later)

Hope this helps!

See Ya!

P.S. Stay Safe!

8 0
3 years ago
Read 2 more answers
Determine whether each question below is a statistical question. Write "yes" or "no" in the spaces provided.
nikdorinn [45]

Answer:

a yes

b no

c no

d yes

e yes

f no

7 0
3 years ago
PLSS ANSWER MY QUESTION
Taya2010 [7]

Answer:

1) Area of frame: 140cm^2 ; Area of picture: 40cm^2 ; Total Area: 180cm^2.      

2) Area 1 =  48cm^2 ; Area 2 = 12cm^2 ; total area = 60cm^2 [first answer line : 60cm^2]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40].  [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as 140cm^{2} ; and the area of the photo should be written as 40cm^{2})

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as 180cm^2)

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as 48cm^{2} ; the area 2 should be written as 12cm^2)

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: 60cm^2)

The area of the figure is 60cm^2

8 0
2 years ago
Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s a
Nimfa-mama [501]

Answer:

Step-by-step explanation:

When Riko left his house, Yuto was 5.25 miles along the path.

Average speed of Riko = 0.35 miles per minute

Average speed of Yuto = 0.25 miles per minute

First we will calculate the time in which Riko will catch Yuto on the track.

Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto

= 0.35 - 0.25

= 0.10 miles per minute

Now we this relative velocity tells that Riko is moving and Yuto is in static position.

By the formula,

Average speed = \frac{Distance}{Time}

0.10 = \frac{5.25}{t}

t = \frac{5.25}{0.1}

t = 52.5 minutes

Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.

So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5

Here time can not be less than zero because time can not be with negative notation. It will always start from 0.

3 0
4 years ago
Read 2 more answers
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