I will suppose that your queation is 10<x<y<14
there are only two odd between 10 and 14
which are 11 and 13
since x is smaller than y
x=11 and y=13
there sum will be x+y=11+13=24
<span>Solve for "x":
a/x = x/4a
---
x^2 = 4a^2
x = 2a</span>
Answer:
$311.42
Step-by-step explanation:
assuming he would have $0.00 dollars left over after the checks. add the checks together then add the deposits together then subtract.
767.03 - 455.61 = 311.42
Answer: d
Step-by-step explanation:
