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anzhelika [568]
2 years ago
15

What is correct A, B or C

Mathematics
1 answer:
Whitepunk [10]2 years ago
3 0

Answer:

A is the correct solution

Step-by-step explanation:

     3x³ + 4x² + 0x - 1  /  x - 2

    <u>          3      10    20</u>

-2 | 3       4       0    -1

 -  (<u>3      -6</u>)

             10       0

      -     <u>(10    -20)</u>

                      20    -1

                 -   (<u>20  -40</u>)

                              39

3x² + 10x + 20 + 39/(x - 2)

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Answer:

The answer is 13 for the surface area

Step-by-step explanation:

5 0
3 years ago
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Need help can someone plz help me solved this problem ASAP! Need help I will mark you as brainiest
erik [133]

Answer: 22, 38

               3, 7

               8, 12

<u>Step-by-step explanation:</u>

It is given that the PERIMETER is BETWEEN 22 and 38

-->          22 < P < 38

Perimeter = 2w + 2L

It is given that L = w + 5

Substitute P with 2w + 2L and substitute L with w + 5

                22 <  2w + 2(w + 5) < 38

                 22 < 2w + 2w + 10 < 38    

                  12 <          4w        < 28    

-->               3 <          w          < 7          

Since L = w + 5, then w = L - 5

Substitute P with 2w + 2L and substitute w with L - 5

                22 <  2(L - 5) + 2L < 38

                 22 < 2L + 2L - 10 < 38    

                 32 <          4L        < 48    

-->               8 <            L        < 12  

7 0
3 years ago
Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0
erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

For calculating the zeros,

\Rightarrow f(x)=0

\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0

\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0

\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0

\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0

\Rightarrow (x-2)(x^2-1)(2x-3)=0

\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0

\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0

\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}

From all the 4 roots, it can be obtained that 2 is the greatest zero.

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Step-by-step explanation:

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