3 years ago

Solve the equation: 6-3(-2-4x)= 2(3(x-4)+7)

Mathematics

1 answer:

Ulleksa [173]3 years ago

5 0

Answer:

the answer is d: x=-11/3

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B16%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B64%7D%20" id="TexFormula1" title

Alja [10]

The answer is:

$4\sqrt{2}$

Further explanation:

Given expression is a radical expression. Radical expressions involve fractional exponents.

Given:

$\sqrt[4]{16}\ *\ \sqrt[4]{64}$

Factorizing 16 and 64

$=\sqrt[4]{2*2*2*2}*\sqrt[4]{2*2*2*2*2*2}\\=\sqrt[4]{2^4} *\sqrt[4]{2^4*2^2}\\Can\ also\ be\ written\ as\\=\sqrt[4]{2^4} *\sqrt[4]{2^4}*\sqrt[4]{2^2}\\={(2^4)}^{\frac{1}{4}}*{(2^4)}^{\frac{1}{4}}*{(2^2)}^{\frac{1}{4}}\\=2*2*{(2)}^{\frac{1}{2} }\\=4*\sqrt{2}\\=4\sqrt{2}$